Given that question: Shyam invested money in the stock market. In the first
year, his stock increased 20%. He paid his stock broker $300 and then lost
$450. He withdrew $500, and then his remaining investment doubled. Shyam’s investment is now worth $7100. How much was Shyam’s original investment?
The solution is as follows:
Let the amount Shyam invested in the stock market be x, then in the first year his stock increased by 20% giving 1.2x.
He paid his stockbrocker $300 to have 1.2x - $300 left, and he lost $450 to have 1.2x - $300 - $450 = 1.2x - $750 left.
He withdrew $500 to have 1.2x - $750 - $500 = 1.2x - $1,250 left.
His remaining investment doubled to have 2(1.2x - $1,250) = 2.4x - $2,500
Shyam's investment is now worth $7,100 which means that
2.4x - $2,500 = $7,100
2.4x = $7,100 + $2,500 = $9,600
x = $9,600 / 2.4 = $4,000
Therefore, the value of Shyam's original investment is $4,000
The answer is B, you’re welcome
Answer:
x−2/x+3
Step-by-step explanation:
(x−3)(x−2)/(x+3)(x−3)
so (x−3) will be cancelled from both denominator and nominator
(x−2)/(x+3)
Answer:
r = 100 cm
Step-by-step explanation:
The radius is 1/2 of the diameter
1/2 d = 1/2(200) = 100
Answer:
160
Step-by-step explanation:
15% + 5% = 20%
80%=0.8
200x0.8=160
