The limit (as 'x' approaches zero) of x²/(2x+1) is
0 / (0+1) = 0 .
You get this by substituting the limit in place of 'x'.
Sometimes that doesn't work. Sometimes it gives you
monstrosities like 0/0, or 1/0, or ∞/∞ .
But it works for this one. There's nothing wrong with 0/1 = zero .
Replace x with -2 and solve:
A) -2 + -2 = -4 which is not less than or equal to -8
B) 2 + -2 = 0, this is greater than or equal to -8
C) -2 + -2 = -4, this is not less than -8
D) 2 + -2 = 0, this is not greater than 8
Answer: B is true
4 and 6!
4*6 = 24
24 - 14 = 10
4 + 6 = 10
