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OLEGan [10]
4 years ago
9

Calculate 6 3/4 & on tax $2,305

Mathematics
1 answer:
drek231 [11]4 years ago
5 0

6 (3/4) = .0675

2,305.00 * .0675 =155.59

Brainiest please  

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In the figure below, △ A B C ∼△ D E F . BX and EY are altitudes of each triangle. Find the measure of EY to the nearest tenth.
Elena-2011 [213]

Answer:

EY = 5.3 cm

Step-by-step explanation:

∵ Δ ABC similar to ΔDEF

∴ AB/DE = BX/Ey

∵ AB = 12 cm

∵ DE = 8 cm

∵ BX = 8 cm

∴ 12/8 = 8/EY

∴ 12EY = 8 × 8 ⇒ 12AY = 64

∴ EY = 64 ÷ 12 = 5.3333 ≅ 5.3 cm

8 0
3 years ago
Can you help me please
Ugo [173]

Answer:

√6x²×√18x²

x²√(6×18)=x²√108=2×3x²√3=6x²√3

4 0
3 years ago
As part of their business promotional package, the Milwaukee Chamber of Commerce would like an estimate of the mean cost per mon
Morgarella [4.7K]

Answer:

a) 884-2.426\frac{50}{\sqrt{40}}=864.82    

884+2.426\frac{50}{\sqrt{40}}=903.179    

So on this case the 98% confidence interval would be given by (864.82;903.179)

b) For this case the upper bound of the confidence interval is lower than 950 so we don't have a significant evidence to conclude that the true mean is 950 per month

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=884 represent the sample mean

\mu population mean (variable of interest)

s=50 represent the sample standard deviation

n=40 represent the sample size  

Solution to the problem

Part a

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=40-1=39

Since the Confidence is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.01,39)".And we see that t_{\alpha/2}=2.426

Now we have everything in order to replace into formula (1):

884-2.426\frac{50}{\sqrt{40}}=864.82    

884+2.426\frac{50}{\sqrt{40}}=903.179    

So on this case the 98% confidence interval would be given by (864.82;903.179)

Part b

For this case the upper bound of the confidence interval is lower than 950 so we don't have a significant evidence to conclude that the true mean is 950 per month

3 0
3 years ago
what force is needed to accelerate a car with a mass of 950 kg that accelerates at a rate of 5.0 m/s^2
NNADVOKAT [17]
F = m x a
f = 950 x 5
f = 4750N
8 0
3 years ago
You have Q quarters, D dimes, and N nickels. You then pay for candy with 4 quarters, 5 dimes, and 6 nickels. Write an expression
zloy xaker [14]

In cents, before you buy the candy, you have 25q, + 10d +5n. The numbers represent the amount of money each coin is worth, and the variable represents how many of each coin there are.


The amount you spend on candy: 4(25) + 5(10) + 6(5) = 180.


Therefore, after you purchase the candy, you have 180 - 25q + 10d + 5n.

I hope this helps!

4 0
3 years ago
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