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schepotkina [342]
3 years ago
11

A television camera at ground level is filming the lift-off of a space shuttle at a point 750 meters from the launch pad. Let θ

be the angle of elevation of the shuttle and let s be the distance between the camera and the shuttle (see figure). Write θ as a function of s for the period of time when the shuttle is moving vertically. Differentiate the result to find dθ / dt in terms of s and ds / dt.
Mathematics
1 answer:
ss7ja [257]3 years ago
7 0

750 * x =

0^1 = 0 =

750 x 0 = 750

A: 750 meters

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Find the sum or difference<br><br> 5+10= ?
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5+10=15
or 1+1+1+1+1+1+1+1+1+1+1+1+1+1+1

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F(x)= x^2+6 and g(x)=x+8/x find( g o f)(-7)
cestrela7 [59]
F(-7) = (-7)^2 + 6 = 49 + 6 = 55;
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5 0
3 years ago
)Suppose ABC is a right triangle with sides of lengths a, b, and c and right angle at C. Find the unknown side length using the
konstantin123 [22]

Answer:

a=\sqrt{7}

\text{tan}(A)=\frac{\sqrt{7}}{3}

Step-by-step explanation:

Please find the attachment.

We have been given that ABC is a right triangle with sides of lengths a, b, and c and right angle at C.  

To find the side length a, we will Pythagoras theorem, which states that the sum of squares of two legs of a right triangle is equal to the square of the hypotenuse of right triangle.

a^2+b^2=c^2

Upon substituting our given values in Pythagoras theorem, we will get:

a^2+3^2=4^2

a^2+9=16

a^2+9-9=16-9

a^2=7

Take square root of both sides:

a=\sqrt{7}

Therefore, the length of side 'a' is \sqrt{7} units.

We know that tangent relates opposite side of a right triangle with adjacent side.

\text{tan}=\frac{\text{Opposite}}{\text{Adjacent}}

We can see that 'a' is opposite side of angle A and 'b' is adjacent side.

\text{tan}(A)=\frac{a}{b}

\text{tan}(A)=\frac{\sqrt{7}}{3}

Therefore, the value of tan(A) is \frac{\sqrt{7}}{3}.

3 0
3 years ago
what is the explicit formula and recursive formula of the numbers 4,7,10,13,16...i don't even know how to start this problem. i
Lana71 [14]

An arithmetic sequence is a sequence with a constant

<span> increase or decrease also known as the </span>constant difference

In the sequence 10, 40, 70, 100, ….

The constant difference between the terms is 30

A recursive formula for a sequence would be:

a1= first term in the sequence

an = term you are trying to find

an-1 = previous term in the sequence

d = constant difference

Explicit Formulas: 

A formula that allows you to find the nth term of the sequence by substituting known values in the expression.

Formula : an = a1 + d( n - 1)

a1= first term in the sequence

an = current term in the sequence

d = constant difference

n = term number

Solution: 

<span>Write the explicit formula of the sequence 4, 7, 10, 13, 16 ….</span>

Formula for explicit term:

an = ___ + ___( n - 1)

Simplify: an = ___ + ___n

In the sequence 4, 7, 10, 13, ….

To find the 11th<span> term explicitly, I plug in the into the formula I just made:  </span>

an = 1 + 3n

a11<span> = 1 + 3(11)  </span> 

a11<span> = 34  </span>

Find the 15th term of the sequence using the formula: an = 1 + 3n

Write the recursive formula of the sequence 4, 7, 10, 13, ….

Recursive formula:

a1 =

an = a  n  - 1

In the sequence 4, 7, 10, 13, 16 ….

To find the 5th<span> term recursively, I plug it into the formula I just made:  </span>

<span>  a</span>n = an-1 + 3

a5 = a5-1<span> + 3   in words: 5</span>th<span>  term equals the 4</span>th term plus 3

a5<span> = 13 + 3  </span>

a5<span> = 16   </span>

Recursive and Explicit Formulas for Arithmetic (Linear) Sequences


8 0
3 years ago
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