Answer:
The height of deepness of submarine is 424.1 feet
Step-by-step explanation:
Given as :
The angle at which submarine drives of the surface of water = Ф = 13°
The speed at which submarine travel = s = 760 feet per minute
Let The height of deepness of submarine = h feet
The time taken to reach that deepness = t = 5 minutes
<u>According to question</u>
The height of deepness of submarine = 
i.e h × cos(90 - Ф) = 
Or, h × Sin(Ф) = 
Or, h × Sin(13°) = 95 feet
Or, h × 0.224 = 95 feet
∴ h = 
i.e h = 424.10 feet
So, The height of deepness of submarine = h = 424.10 feet
Hence, The height of deepness of submarine is 424.1 feet Answer
Answer:
745 k/hr
Step-by-step explanation:
mathematically, 1 day = 24 hours
1670 days = 1670 * 24 = 40,080 hours
The speed is thus;
(29,870,000)/40,080 = 745.259
= 745 km/h
The answer is D,I might be wrong tho