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jeyben [28]
3 years ago
11

No real numbers are irrational numbers

Mathematics
2 answers:
qaws [65]3 years ago
7 0
True. A rational number is a number that can be put into a fraction and all real numbers can in the form of x/1
BaLLatris [955]3 years ago
4 0
Yes you are right no irrational numbers can be written as real numbers

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luis wants to buy a skateboard that usually sells for $79.99. all merchandise is discounted by 12%. what is the total cost of th
aivan3 [116]

<u>ANSWER: </u>

The total cost of the skate board is $74.61.

<u>SOLUTION: </u>

Given, Luis wants to buy a skateboard that usually sells for $79.99. all merchandise is discounted by 12%. luis has to pay a state sales tax of 6.75%.  

We need to find what is the total cost of the skateboard.

Final cost is nothing but original amount subtracted by discount and added with tax.

final cost = original cost – discount + sales tax

Original cost = $79.99

Discount = 12% of original cost

\begin{array}{l}{=12 \% \times 79.99} \\\\ {=\frac{12}{100} \times 79.99} \\\\ {=\frac{959.88}{100}} \\\\ {=9.5988}\end{array}

discount is $9.6 approximately

Sales tax = 6% of cost after discounting

\begin{array}{l}{=6 \% \times \text { (original cost - discount) }} \\\\ {=\frac{6}{100} \times(79.99-9.6)} \\\\ {=\frac{6}{100} \times(70.39)} \\\\ {=\frac{422.34}{100}} \\\\ {=4.2234}\end{array}

Sales tax is $4.22 approximately

Now, final cost = 79.99 – 9.6 + 4.22

= 84.21 - 9.6

= 74.61

Hence, the total cost of the skate board is $74.61

6 0
3 years ago
If M is the Midpoint of AB, then solve for x find the unknown measures the given segments.
Leto [7]

Answer:

If M is midpoint of AB, then

AM=MB

4x-5= 2x+11

2x=16

x=8

AM= 4x-5

=4(8)-5

=32-5

=27

BM=2x+11

=2(8)+11

=16+11

=27

Hope it helps:-)

8 0
3 years ago
I have one hundred eighty two figures and sevendy five figures how many do i have in total
Andrei [34K]
You would have two hundred and fifty seven figures.
4 0
3 years ago
Read 2 more answers
Show that ( 2xy4 + 1/ (x + y2) ) dx + ( 4x2 y3 + 2y/ (x + y2) ) dy = 0 is exact, and find the solution. Find c if y(1) = 2.
fredd [130]

\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}

\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}

so the ODE is indeed exact and there is a solution of the form F(x,y)=C. We have

\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)

\dfrac{\partial F}{\partial y}=4x^2y^3+\dfrac{2y}{x+y^2}=4x^2y^3+\dfrac{2y}{x+y^2}+f'(y)

f'(y)=0\implies f(y)=C

\implies F(x,y)=x^2y^3+\ln(x+y^2)=C

With y(1)=2, we have

8+\ln9=C

so

\boxed{x^2y^3+\ln(x+y^2)=8+\ln9}

8 0
2 years ago
Which of the following is true of the discriminant for the graph below?
Sonbull [250]

Answer:

<u>Option C. It is zero</u>

Step-by-step explanation:

The graph represents a quadratic equation

The quadratic equation has the form ⇒a x² + b x + c

The discriminant of the quadratic equation is D = b² - 4ac

From the discriminant of the quadratic equation, we can know the type of roots of the quadratic equation.

  1. If D > 0 ⇒ Two real roots.
  2. If D = 0 ⇒ one real roots
  3. If D < 0 ⇒ Two imaginary roots.

The roots of the quadratic equation are the x-intercepts of the function.

As shown at the figure, the quadratic equation has only one point of intersection with the x-axis

So, the function has only one root ⇒ D = 0

So, the discriminant of the quadratic equation = 0

<u>The answer is option C. It is zero</u>

7 0
2 years ago
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