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3 years ago

How many solutions does each equation below have? how can you tell?

1 answer:

8 0

A) This one has no solutions because the answer of the equation is 0=-1 which isn't true.

b) 6t-3=3t+6 ==> 3t=9 ==> t=3 This means that this has one solution.

c) 6 (2m-3)-3m=2m-18+m ==> 12m-18=2m-18+m ==> 9m=0 ==> m=0 so this one has no solutions.

d) 10+3y-2=4y-y+8 ==> 8+3y=3y+8 ==> 0=0 ==> Infinitely many solutions.

~Hope I helped!~

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52.5% of what number is 25.83?

xxTIMURxx [149]

Given:
25.83 - part
52.5% percentage of the part against the whole

To get the whole number, we need to divide the part by its corresponding percentage.

25.83 ÷ 52.50% = 49.20

49.20 is the whole number wherein 25.83 represents 52.50% of it.

6 0

3 years ago

Isabella's house has 3 bedrooms. Each bedroom is 12 feet long, 10 feet wide, and 8 feet high. Isabella must paint the walls of a

san4es73 [151]

Answer:

876 square feet need to be painted.

Step-by-step explanation:

There are four walls in each bedroom, since she can't paint floors or ceilings. So we calculate the number of square feet of wall there is in one bedroom

(12*8)+(12*8)+(10*8)+(10*8)-60=160+192-60=292

There are 3 bedrooms so

292*3=876

6 0

3 years ago

Expanding logarithmic Expression In Exercise,Use the properties of logarithms to rewrite the expression as a sum,difference,or m

aliina [53]

Answer:

$\ln x(x^2 + 1)^\frac{1}{3} = \ln x + \dfrac{1}{3} \ln (x^2 + 1)$

Step-by-step explanation:

We are given the following expression in the question

$\ln x(x^2 + 1)^\frac{1}{3}$

Logarithmic Properties:

$\log (ab) = \log a + \log b\\\\\log \dfrac{a}{b} = \log a - \log b\\\\\log (a^b) = b\log a$

We have to simplify the given expression

$\ln x(x^2 + 1)^\frac{1}{3}\\=\ln x + \ln (x^2 + 1)^\frac{1}{3}\\\ln x + \dfrac{1}{3} \ln (x^2 + 1)$

$\ln x(x^2 + 1)^\frac{1}{3} = \ln x + \dfrac{1}{3} \ln (x^2 + 1)$

6 0

3 years ago

Read 2 more answers

Find four consecutive odd integers such that 3 times the sum of the 1st and 2nd is 15 less than the fourth

jeka94

Answer: How do you find you four consecutive odd integers such as three times the sum of the first and the second is 15 less than the fourth?

Step-by-step explanation: So, the normal consecutive integers numbers are: 2,3,4,5. And the even consecutive integers numbers are: 2,4,6,8. And the odd consecutive integers are: 3,5,7,9. Consecutive integers formula are the algebraic representations of the consecutive integers. The formula to get a consecutive integer is n + 1.

Same as above, 7 is one of 4 consecutive integers, then the result is only 4 cases:

, 5, 6, 7

, 6, 7, 8

, 7, 8, 9

, 8, 9, 10

Hope this helps.

7 0

2 years ago

Subtract (3 + 9i) from (–2 +17i).

pashok25 [27]

Answer:

$-5+8i$

Step-by-step explanation:

$(-2+17i)-(3+9i)\\=-2+17i-3-9i\\=-2-3+17i-9i\\=-5+8i$

7 0

3 years ago