Answer: scalene and obtuse
Justification:
You can find the angles using the law of cosine:
c^2 = a^2 + b^2 - 2abcos(γ)
=> cos(γ) = [a^2 + b^2 - c^2] / (2ab)
1) cos(γ) = [10^2 + 11^2 - 15^2] / (2*10*11) = - 0.0181818
=> γ = arccos(-0.0181818} ≈ 91°
2) cos(α) = [b^2 + c^2 - a^2 ] / 2bc = [11^2 + 15^2 - 10^2] / (2*11*15] = 0.7454545
=> α = arccos(0.7454545) ≈ 41.8°
3) cos(β) = [a^2 + c^2 - b^2] / (2ac) = [10^2 + 15^2 - 11^2] /(2*10*15) = 0.68
=> β = arccos(0.68) ≈ 47.2°
4) Verification: 91° + 41.8° + 47.2° = 180°
5) The triangles with the three different sides are called scalenes (which you can tell with only the measures of the sides).
6) The triangles with one angle greater than 90° are called obtuse.
So, the triangle is scalene and obtuse.
Answer:
793.25 mi/hr
Step-by-step explanation:
Given that:
The radius of the earth is = 3030 miles
The angular velocity = 
If a jet flies due west with the same angular velocity relative to the ground at the equinox;
We are to determine the How fast in miles per hour would the jet have to travel west at the 40th parallel for this to happen.
NOW;
Distance s is expressed by the relation
s = rθ
s = 793.25
The speed which depicts how fast in miles per hour the jet would have traveled is :
v = 793.25 mi/hr
Hence, the jet would have traveled 793.25 mi/hr due west at the 40th parallel for this to happen.
The dimension of the document is 35 inches by 40 inches.
It is redrawn at a scale of 1 1/2 or 3/2 or 1.5
The dimension will be:
35 * 1.5 = 52.5 in
40 * 1.5 = 60 in
Then redrawn again at 1/4 or 0.25
52.5 * 0.25 = 13.125 in
60 * 0.25 = 15 in
So the final dimensions of the drawing is 13.125 in by 15 in
It should be B based off the shaded area
