Given that JKLM is a rhombus and the length of diagonal KM=10 na d JL=24, the perimeter will be found as follows;
the length of one side of the rhombus will be given by Pythagorean theorem, the reason being at the point the diagonals intersect, they form a perpendicular angles;
thus
c^2=a^2+b^2
hence;
c^2=5^2+12^2
c^2=144+25
c^2=169
thus;
c=sqrt169
c=13 units;
thus the perimeter of the rhombus will be:
P=L+L+L+L
P=13+13+13+13
P=52 units
The translation of the sum a and n is a+n
Let T be the taco, B the burrito, MP the mexican pizza, R the rice, and N the beans.
For the main course we can have the first three.
----- T
------ B
-------MP
Each main course comes with the two sides. So an R branch and a B branch go to each of the taco, burrito, or pizza.
-----T---------R or N.
We expand it to
--------T-----------R
---------------------N
And we repeat it for the rest.
Thus, the tree diagram is
----- T --------R
-----------------N
-----B---------R
-----------------N
----MP--------R
----------------N
Answer:
0.128
Step-by-step explanation:
We know the probability for any event X is given by,
,
where p is the probability of success and q is the probability of failure.
Here, we are given that p = 0.533.
Since, we have that q = 1 - p
i.e. q = 1 - 0.533
i.e. q = 0.467
It is required to find the probability of 4 wins in the next 5 games i.e. P(X=4) when n = 5.
Substituting the values in the above formula, we get,
i.e. 
i.e.
i.e. i.e. 
Hence, the probability of 4 wins in the next 5 games is 0.128.
