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denis-greek [22]
3 years ago
7

Find the solutions to the equation below check all that apply 30x^2-26x+4=0

Mathematics
2 answers:
-BARSIC- [3]3 years ago
5 0

Answer:

A. 1/5

C. 2/3

Step-by-step explanation:

30x^2 - 26x + 4=0

2(15x^2 - 13x + 2) = 0

2(15x^2 - 10x - 3x  + 2) = 0

2[(5x(3x - 2)  - 1(3x - 2)] = 0

2(5x - 1)(3x - 2) = 0

5x - 1 = 0; x = 1/5

3x - 2 = 0; x = 2/3

IgorC [24]3 years ago
3 0

Answer:

x = 1/5, x = 2/3.

Step-by-step explanation:

30x^2 - 26x + 4 = 0

15x^2 - 13x +2 = 0

(5x - 1 )(3x  - 2) = 0

5x - 1 = 0  or 3x - 2 = 0

x =  1/5,  2/3.

You might be interested in
The nth term of a sequence is given by 20-n^2 a) find the third term of the sequence b) which term in the sequence is the first
ehidna [41]

Answer:

The third term is 11.

The first negative term is the fifth term.

Step-by-step explanation:

If the nth term of the sequence is given by the expression 20-n^2, to find the third term, we just need to use the value of n = 3 in the expression:

20 - (3)^2 = 20 - 9 = 11.

To find which term is the first to have a negative value, we can solve the inequation 20 - n^2 < 0:

20 - n^2 < 0

n^2 > 20

n > 4.47

The first term to have a negative value is the fifth term:

20 - 5^2 = 20 - 25 = -5

5 0
4 years ago
Please help me out with this problem. will give thanks!
ioda

Answer:

It is an isosceles  triangle.

Step-by-step explanation:

sum of angles of triangle = 180

since it is isosceles two angles will be same. let it be x.

x + x + 22 = 180

2x = 180 - 22

2x = 158

x = 79°

7 0
3 years ago
Can somebody help teach me how to solve quadratic equations? I have no idea what to plug in. Here are some examples of what I ne
guapka [62]
The best method that will work for any quadratic equation is to use the quadratic formula: x = (-b±√(b² - 4ac))/2a, this will work for any quadratic of the form ax² + bx + c = 0.

As for the last equation in the attachment, that is a cubic equation, these are much trickier to solve and as such the formula is much longer and very complicated. Therefore it is easier to see if it can be broken down into a linear term and a quadratic. This can be done by substituting integer values of x into the equation to see if it holds true. If both sides of the equation are equal for a given value of x then the equation ax³ + bx² + cx + d can be rewritten as (Ax + B)(px² + qx + r). This can then be put into the quadratic formula mentioned above.
4 0
3 years ago
Which description is correct for the polynomial 2x^2+2?
balu736 [363]
The answer is A. Quadritic trinomial. i hope it helps
3 0
3 years ago
Read 2 more answers
Plz help on rationalising surds
Fittoniya [83]
(√5 + 3)² / √20=
((√5 + 3)² / √20)(√20/√20)=
(√20(√5 + 3)²) / (√20)²=
√20(5+6√5+9) /20=
√20 (14+6√5) /20=
(14√20 +6√100) /20=
(14√20 +60) / 20=
(14(√4√5) + 60) /20=
(14(2)(√5)+60) / 20=
(28√5+60) /20=
(7√5+15) / 5

Answer:(√5 + 3)² / √20= <span>(7√5+15) / 5</span>
3 0
3 years ago
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