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shepuryov [24]
3 years ago
12

mrs tart takes a survey she discovers 60% of her students prefer using pens over pencils in class. if 12 students in Mrs. Tart c

lass prefer to use pens how many total students are in mrs. tarts class
Mathematics
2 answers:
Rudik [331]3 years ago
8 0
20 ? i think that is right
mojhsa [17]3 years ago
5 0

Answer:

20

Hope this helps :D

           

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The owner of a retail store is tracking his inventory for an annual report. The graph shows the remaining inventory for a partic
aliina [53]
Y = -2.8x +69.4

Let y represent units of inventory, and x represent days since the last replenishment. We are given points (x, y) = (3, 61) and (13, 33). The line through these points can be described using the 2-point form of the equation of a line:
... y -y1 = (y2-y1)/(x2 -x1)(x -x1)
Filling in the given point values, we have ...
... y -61 = (33 -61)/(13 -3)(x -3)
Simplifying and adding 61, we get ...
... y = -2.8x +69.4
5 0
2 years ago
50 please help on these questions!
saul85 [17]

Answer:

pic1=56-28x

pic2=3cd+12c

pic3=s−t

pic4= the last answer

pic5= the third answer

Step-by-step explanation:

i did the math so just trust me

6 0
2 years ago
AABC ~ AQRS
Mademuasel [1]

Answer:

m=21

Step-by-step explanation:

based on the dilation from 'ABC' to 'QRS' (which is 3) m should =21

hope this helps! :)

3 0
3 years ago
(a) Find the remainder when 15! is divided by 17. (b) Find the remainder when 2(26!) is divided by 29, Thatermine whether 17 is
dlinn [17]

Answer:

Step-by-step explanation:

a) We have 15! as the product of 1 to 15 natural numbers.  Since 17 is prime there will be no factor common to these

By actual division we find

15! (mod 17) =16

From this we deduce

even 16! mod 17 = 16 = -1

According to Wilson theorem

(17-1)! = -1 mod 17

Thus verified 17 is prime

Hence 15! (mod 17) =-1=16

-----------------------

b) 2(26!) is divided by 29

Since 29 is prime

(29-1)! = -1 mod 29

28! = -1 mod 29 = 28

When divided this gives 25 as remainder

4 0
3 years ago
How to I solve problem 1?
Verdich [7]
#1

The uniforms are numbered 0, 1, 2, ..., 99. That's 100 numbers. Half of them are odd and half of them are even. So the probability that any one of the uniforms is odd is 1/2 just like the probability that any one uniform is even is 1/2.

(a) The numbers on the uniforms are independent of one another. That is, the number of her cross-country uniform does not in any way determine the number on her basketball uniform and vice versa. This means that we can find the probability that each is odd and multiply these together using what is called the counting principle. The probability that all are odd is:
(1/2)(1/2)(1/2)=1/8

(b) This is done the same way we did part (a). Since the probability of any one uniform being odd is the same as it being even (1/2), the answer here is the same: (1/2)(1/2)(1/2)=1/8

(c) This problem differs from that in (a) and (b). There is only one way for all three uniforms to be odd numbers: (odd, odd, odd) or all even (even, even, even). However, there are multiple ways for the uniforms to be two odd and one even. If the uniforms are listed in order: cross-country, basketball, softball we can get exactly one even in any of three ways:
even, odd, odd
odd, even, odd
odd, odd, even
The probability for any one of these possibilities is (1/2)(1/2)(1/2)=1/8 but since there are three way the probability that we get even exactly once is equal to (3)(1/8) = 3/8
7 0
3 years ago
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