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Ann [662]
3 years ago
13

Alex ran 12.8 km in the morning. After​ lunch, he continued running. When he finished the​ run, he had covered 31.4 km in all. W

rite an equation that can be used to find how far Alex ran after lunch.
Let r be the distance in kilometres that Alex ran after lunch.
Mathematics
1 answer:
Ulleksa [173]3 years ago
3 0

Answer:

12.8 km + r = 31.4 km

Step-by-step explanation:

First, Alex ran 12.8 km, then he ran an r amount of km. Added together they equal 31.4 km.

If you need to solve the equation you subtract 12.8 from 31.4 and will give you the amount of miles he ran after lunch.

Ex.: r = 31.4 km - 12.8 km

      r = 18.6 km

Alex ran 18.6 km after lunch

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Total distance walked by Tarik is 0.75 miles according to the given equation.

What is equation?

In arithmetic, an equation could be a formula that expresses the equality of 2 expressions, by connecting them with the sign =.

Main body:

Given that

The expression that represents the Tarik's distance is

=>  f(x) = 3∣x−0.5∣

And also given that at 7.15 am he is some distance away from the store

Let Tarik is 'a' miles away from the store at 7.15 am

The time taken to walk 'a' miles = 7.15 - 7.00 = 15 minutes

As we know 60 minutes = 1 hr

=> 15 minutes = 15/60 = 0.25 hrs  

The given expression to find the Distance is

f(x) = 3 ∣x − 0.5∣    where x is number of hours

At x = 0.25

f(0.25) = 3 |0.25 - 0.5|

= 3 |- 0.25|

= 0.75 miles

Therefore,Tarik is 0.75 miles away from the store.

To know more about equation , visit:

brainly.com/question/22688504

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8 0
1 year ago
Answer this question​
PolarNik [594]

Answer:

(0,8)

Step-by-step explanation:

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2 years ago
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Determine the equation of the following polyromial that passes through point (0,6).
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Answer:

Cubic polynomial has zeros at x=−1x=−1 and 22, is tangent to x−x−axis at x=−1x=−1, and passes through the point (0,−6)(0,−6).

So cubic polynomial has double zero at x=−1x=−1, and single zero at x=2x=2

f(x)=a(x+1)2(x−2)f(x)=a(x+1)2(x−2)

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a(1)(−2)=−6a(1)(−2)=−6

a=3a=3

f(x)=3(x+1)2(x−2)f(x)=3(x+1)2(x−2)

f(x)=3x3−9x−6

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