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nikitadnepr [17]
3 years ago
13

A tree casts a 25 foot shadow. At the same time of day, a 6 foot man standing near the tree casts a 9 foot shadow. What is the a

pproximate height of the tree to the nearest foot?
Mathematics
2 answers:
cupoosta [38]3 years ago
6 0
<span>The man casts a shadow that is 1.5 times his height. 
Divide the tree's shadow by 1.5 to find its height 
25 / 1.5 = 16.6666666 approximate to 17 feet.</span><span>

</span>
EleoNora [17]3 years ago
4 0
I think the answer is 16.667 ft . 
I hope this helps!
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Answer:

\frac{5}{2} ounces of marigold seeds.

Step-by-step explanation:

We have been given that Jane uses 2/5 of an ounce of lupine seeds for every ounce of Marigold seeds. We are asked to find the ounces of Marigold seeds, which Jane will use, if she used one ounce of lupine seeds.  

We will use proportions to solve our given problem.  

\frac{\text{Marigold seeds}}{\text{Lupine seeds}}=\frac{1}{\frac{2}{5}}

Let us simplify our proportion as shown below:

\frac{\text{Marigold seeds}}{\text{Lupine seeds}}=\frac{1\cdot 5}{2}

\frac{\text{Marigold seeds}}{\text{Lupine seeds}}=\frac{5}{2}

Since Jane used 1 pounce of lupine seeds, so we will substitute this value in our proportion as:

\frac{\text{Marigold seeds}}{1}=\frac{5}{2}

\text{Marigold seeds}}=\frac{5}{2}

Therefore, Jane will use \frac{5}{2} ounces of marigold seeds, if she used one ounce of lupine seeds.

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3 years ago
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A = L * W = 75 so L = 75/W Cost = 4W + 8(2L + W) = 4W + 16L + 8W = 12W + 16L = 12W + 1200/W C' = (12(W^2 - 100))/(W^2) = (12(W-10)(W+10))/(W^2) so W = 10 then L = 7.5
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Step-by-step explanation:

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Step-by-step explanation:

Given

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Step-by-step explanation:

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