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Marianna [84]
3 years ago
12

The test statistic of zequalsnegative 1.54 is obtained when testing the claim that pless than0.18. a. Using a significance level

of alphaequals0.05​, find the critical​ value(s). b. Should we reject Upper H 0 or should we fail to reject Upper H 0​?
Mathematics
1 answer:
Rom4ik [11]3 years ago
7 0

Answer:

(a) The z-critical value for a left-tailed test, for a significance level of α=0.05 is -1.64.

(b) Since -1.54 > -1.64, therefore we accept H₀.

Step-by-step explanation:

(a)

It is given that the value of test statistic is

z=-1.54

We need to test the claim that p<0.18.

Null hypothesis: H_0:p=0.18

Alternative hypothesis: H_1:p

It is a left tailed test.

Significance level:

\alpha=0.05

The z-critical value for a left-tailed test, for a significance level of α=0.05 is -1.64.

(b)

It is a left tailed test and critical value is -1.64 it means the region on left of -1.64 is rejection region.

The value of z is -1.54 and the critical value is -1.64.

We know that -1.54 > -1.64.

Therefore we accept H₀.

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Answer:

y=x^2+8x+15

Intercept form is y= (x+5)(x+3)

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Step-by-step explanation:

Given quadratic function

y=(x+4)^2-1

To rewrite it in standard form we need to expand (x+4)^2

y=(x+4)(x+4)-1

y=x^2+8x+16-1

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product is 15 and sum is 8, 5*3= 15 and 5+3=8

(x+5)(x+3)

Intercept form is y= (x+5)(x+3)

Vertex form of equation is y=(x-h)^2+k

where (h,k) is the vertex

y=(x+4)^2-1, here h = -4 and k =1 so vertex is (-4,1)

To find y intercept plug in 0 for x

y= (x+5)(x+3)

y= (0+5)(0+3) = 15, so y intercept is (0,15)

to find x intercept plug in 0 for y

y= (x+5)(x+3)

0= (x+5)(x+3),             x+5 =0           and x+3=0

                                   x=-5              and x= -3

So x intercepts are (-5,0) (-3,0)

6 0
3 years ago
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seraphim [82]
<h2>answer:</h2>

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