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Marianna [84]
3 years ago
12

The test statistic of zequalsnegative 1.54 is obtained when testing the claim that pless than0.18. a. Using a significance level

of alphaequals0.05​, find the critical​ value(s). b. Should we reject Upper H 0 or should we fail to reject Upper H 0​?
Mathematics
1 answer:
Rom4ik [11]3 years ago
7 0

Answer:

(a) The z-critical value for a left-tailed test, for a significance level of α=0.05 is -1.64.

(b) Since -1.54 > -1.64, therefore we accept H₀.

Step-by-step explanation:

(a)

It is given that the value of test statistic is

z=-1.54

We need to test the claim that p<0.18.

Null hypothesis: H_0:p=0.18

Alternative hypothesis: H_1:p

It is a left tailed test.

Significance level:

\alpha=0.05

The z-critical value for a left-tailed test, for a significance level of α=0.05 is -1.64.

(b)

It is a left tailed test and critical value is -1.64 it means the region on left of -1.64 is rejection region.

The value of z is -1.54 and the critical value is -1.64.

We know that -1.54 > -1.64.

Therefore we accept H₀.

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Which of the following graphs could be the graph of the function f(x)=-0.08x(x^2-11x+18)?
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Answer:

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Step-by-step explanation:

f(x)=-0.08x(x^2-11x+18)

Factor the parenthesis and find out the x intercepts

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We find out two factors whose product is 18 and sum is -11

-9  and -2 gives us product 18

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(x^2-11x+18) =(x-9)(x-2)

f(x)=-0.08x(x^2-11x+18)

f(x)= -0.08x(x-9)(x-2)

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x intercepts are (0,0) (2,0)  and (9,0)

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so the graph crosses x -axis at x=0, 2,9

option C is correct

The graph is attached below4


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