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suter [353]
3 years ago
8

Mike drove 10 miles in 30 minutes, what's the average speed in miles per hour

Mathematics
1 answer:
ollegr [7]3 years ago
7 0
Mike is driving 20 miles per hour

If he is driving 10 miles in 30 mins
(1/2 an hour) if you times both by two it tells you the MPH that Mike is driving.
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Solve the system of equations.<br><br> −4x+3y=−2<br> y=x−1<br><br> x-<br> y-<br> ​
Kobotan [32]

Answer: x=  -1

               y= -2

Step-by-step explanation:

-4x+3y= -2

y=x-1

-------------------

-4x+3(x-1)= -2

-4x+3x-3= -2

-x=1

x= -1

y=-1-1

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3 years ago
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What are the answer to this question
IrinaK [193]

Answer: t=-3h+25

Step-by-step explanation:

t=-3h+25

25 degrees is a constant-- it never changes, no matter how many hours goes by. So, you don't multiply a variable with it.

The temperature drops every 3 hours-- this is not constant, since it's dependent on the number of hours that passes. So, use a variable here. Since the temperature drops every three hours, it's -3, and not 3.

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A boy leaves on a bicycle trip at the rate of 8 mph. One hour later the father, realizing that his son forgot his camping
KatRina [158]

Answer:

40 mph

Step-by-step explanation:

One hour includes 60 minutes

8/60=0.13(3 repeating)

You only need 15 minutes of time

0.13(3 repeating)*15=2

8+2=10 miles

15 minutes is 1/4 of an hour

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6 0
3 years ago
Miguel's teacher instructed him to graph the linear equation y = (3/5)x + 1. He
gladu [14]
I think it is C.) (3,6)
5 0
3 years ago
Charlie's garage has a rectangular floor space. Its length is 3 times its width. Charlie extends the width of his garage to 6 m,
MAXImum [283]

Answer:

The percentage change is 140%

Step-by-step explanation:

Given

L= 3W_1 ---- initial dimension

W_2 = 6m --- new width

A_2 = 45m^2 --- new dimension

Required

The percentage increment

The length remains constant because only the width is extended.

The new area is:

Area =Length * Width

A_2=L * W_2

Make L the subject

L = \frac{A_2}{ W_2}

Substitute values for A and W

L = \frac{45m^2}{6m}

L = \frac{45m}{6}

L = 7.5m --- this is the length of the garden

Calculate the initial width:

L= 3W_1

Make W1 the subject

W_1 = \frac{1}{3} * L

W_1 = \frac{1}{3} * 7.5

W_1 = 2.5

So, the initial area is:

A_1 = L_1 * W_1

A_1 = 2.5 * 7.5

A_1 = 18.75

The percentage change in area is:

\%A = \frac{A_2 - A_1}{A_1}

\%A = \frac{45 - 18.75}{18.75}

\%A = \frac{26.25}{18.75}

\%A = 1.4

Express as percentage

\%A = 1.4*100\%

\%A = 140\%

4 0
3 years ago
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