<span>P: y + z = 6
Q: 8y + 7z = 1
A. This makes y = -8Y which will eliminate the "y"'s when the equations are added.
</span>
There are many different equalvelices.3.10 really is like a fraction so...
3/10 is equal to 30/100 and 300/1000.
Surely this should help.
Sense we are wanting to find <u>
how many were miss</u>
, then, we are practically going to subtract the following:
![\boxed{76-100}= \ \left[\begin{array}{ccc}\bf{24\end{array}\right]](https://tex.z-dn.net/?f=%5Cboxed%7B76-100%7D%3D%20%5C%20%20%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cbf%7B24%5Cend%7Barray%7D%5Cright%5D%20)
So, from this begin understood, we would then combine both the penalties that were shotted, to the onces that weren't.
So, b subtracting these both, we would grab the result, and then smash that with the number of the penalties that were made in.
Your answer:
Answer:
4
Step-by-step explanation:
gcf(432,320,228)=gcf(gcf(432,320),228)
432=320(1)+112
320=112(2)+96
112=96(1)+16
96=16(6)
So the gcf(432,320)=16.
So now we need to find gcf(16,228)
228=16(14)+4
16=4(4)
Therefore,
gcf(432,320, 228)
=gcf(gcf(432,320),228)
=gcf(16, 228)=4
===================================
432=4(108)=4(2)(54)
=4(2)(6)(9)=2(2)(2)(2)(3)(3)(3)
320=4(80)=4(2)(40)=2(2)(2)(4)(10)
=2(2)(2)(2)(2)(2)(5)
228=4(57)=2(3)(38)=2(2)(3)(19)
All three of them have 2*2 in commom, so the greatest common factor is 4.