We have given
hypotenuse=<span>6√2
let us suppose leg =a
using Pythagorean theorem
a^2+a^2=(</span><span>6√2)^2
</span>2a^2=36*2
diving by 2 on both sides
a^2=36
taking square root on both sides
√a^2 =<span>√36
a=6
therefore
</span><span>the leg of each isosceles right triangle is 6</span>
Answer:
Step-by-step explanation:
You've typed the equation incorrectly. 3^5x-1 = 3⁵x-1.
It needs to be typed as 3^(5x-1) = 7.
Answer:
A)1,-3
Step-by-step explanation:
X+2y=5
X-3y=7
To write a determinant we take the coefficient of the variables
To get first row we take the coefficients of x and y from the equation x+2y = 5
x or 1x are same
1x+2y = 5
The coefficient of x is 1 and coefficient of y is 2
So first row is 1 , 2
We do the same for second row
To get second row we take the coefficients of x and y from the equation x-3y = 7
1x - 3y = 7
The coefficient of x is 1 and coefficient of y is -3
So second row is 1, -3
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Answer:
6 and 7
Step-by-step explanation:
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