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Serjik [45]
3 years ago
10

Is the statement below always, sometimes, or never true? Give 2 examples to support. LCM of two numbers is the product of the tw

o numbers.
Mathematics
2 answers:
spayn [35]3 years ago
6 0
The statement below is sometimes true. An example of this is with 1 and 2. Their lowest common multiple is 2 and 1 times 2 is 2. So, that's correct. Another example of this is with 2 and 4. Their lowest common multiple is four and 2 times 4 is 2 so that's not always right.
OverLord2011 [107]3 years ago
4 0
It is sometimes true 
One example is the least common multiple of 2 and 3 is 6, which is their product.
<span>But the product isn't always the answer because
 Example 2: the least common multiple of 6 and 10 is 30 because 6*5=30 and 3*10=30, however 6*10 is 60.</span>
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For these questions find the probability of drawing the given cards at random from a standard 52-card deck under each condition:
never [62]

Answer:

2

a) 6.37%

b) 6.25%

3

a) 0.60 %

b) 0.59 %

Step-by-step explanation:

2 )

a) With replacement

Probability of extracting a club is 13/52

Probability of extracting a spade is 13/51

13/52 * 13/51

= 6.37 %

b) Without replacement

13/52 * 13/52

= 6.25 %

3) With replacement

Probability of extracting a ace is 4/52

Probability of extracting a queen is 4/51

4/52 * 4/51

= 0.60 %

b) Without replacement

4/52 * 4/52

= 0.59 %

5 0
3 years ago
Tickets to a museum cost $16 each. For a trip, the museum offers a $4 discount on each ticket. How much will tickets cost for 31
dlinn [17]

Answer:

$372

Step-by-step explanation:

$16-4=12/ticket

$12 x 31=$372

7 0
3 years ago
Please help me with this.
likoan [24]

It is possible for two different inputs to give you the same output. For example, -2 and 2 produce the same result: 5.

it is not possible to derive two different outputs from the same input. This is because a) y=x^2+1 is a function making it impossible to have two outputs and b) for each value, if  you square it, you only get one value, then adding one, making it one certain value.



6 0
3 years ago
She needs to buy at least 100 chairs. Chairs with arms cost $80. Chairs without arms cost $70. Ms. Robinson can spend, at most,
stealth61 [152]

Answer:

50 chairs with arms and 50 without arms will cost $7500

Step-by-step explanation:

Create two equations using the given information. The unknowns are :

W  = Number of chairs with arms

N = Number of chairs with No arms

First equation (associated with the total number of chairs to buy):

W + N = 100

Second equation (associated with the amount to spend):

80 W + 70 N = 7500

Solving: solve for W in the first equation: W = 100 - N

Use it to substitute for W in the second equation:

80 (100 - N) + 70 N = 7500

8000 - 80 N + 70 N = 7500

subtract 8000 from both sides and combine

- 10 N = - 500

Divide both sides by -10 in order to solve for N

N = -500 / (-10) = 50

Now use this value in the substitution equation to solve for W:

W = 100 - 50 = 50

So the person can buy 50 chairs with arms and 50 chairs without arms paying for them $7,500.

8 0
3 years ago
Giving brainliest! View the image!
s2008m [1.1K]

Answer:

A) 15 cm B) 1292 cm^2

Step-by-step explanation:

A) height can be used by using Pythagoras theorem

Height^2+base^2=slant^2

height^2+8^2=17^2

height=15 cm

B) The amount of cardboard used can be found by calculating the area

Area=2*(area of triangle) + 3*(area of rectangles)

17*16+3*(20*17)=1292 cm^2

6 0
3 years ago
Read 2 more answers
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