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2 years ago

14

if i I wanted to be precise, how can I express the exact circumference for the circumference given the diameter

1 answer:

sveticcg [70]2 years ago

6 0

The formula for circumference is $\pi d$ .

To express the circumference exactly, plug the diameter in for $d$ and put the $\pi$ symbol in front of it. Don't multiply. This expresses the exact circumference.

Say you have the diameter of 17.
You can express the circumference with 17 $\pi$ .

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Find the greatest common factor: 9a3bc2 + 12ac4 + 15a2b3c 3abc 15a3b3c4 3ac 9a2b2c2

VARVARA [1.3K]

The greatest common factor is 3abc

8 0

3 years ago

Trey has money saved for a school trip. He earns an additional $40 mowing lawns to add to his savings. Trey's parents give him e

serg [7]

Answer:

234 divided by 2 is 117, he had 117 when he saved up mowing lawns

Step-by-step explanation:

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3 years ago

13 + what = 23.6? I need help i will give u brainlest if you help plz

Bas_tet [7]

Answer:

10.6

Step-by-step explanation:

13+10.6= is 23.6

Hope this helps

3 0

2 years ago

Read 2 more answers

you pick a card at random without getting the first card back you pick a second card at random what is the probability of pickin

Keith_Richards [23]

We have to calculate the probability of picking a 4 and then a 5 without replacement.

We can express this as the product of the probabilities of two events:

• The probability of picking a 4

,

• The probability of picking a 5, given that a 4 has been retired from the deck.

We have one card in the deck out of fouor cards that is a "4".

Then, the probability of picking a "4" will be:

$P(4)=\frac{1}{4}$

The probability of picking a "5" will be now equal to one card (the number of 5's in the deck) divided by the number of remaining cards (3 cards):

$P(5|4)=\frac{1}{3}$

We then calculate the probabilities of this two events happening in sequence as:

$\begin{gathered} P(4,5)=P(4)\cdot P(5|4) \\ P(4,5)=\frac{1}{4}\cdot\frac{1}{3}=\frac{1}{12} \end{gathered}$

Answer: 1/12

8 0

11 months ago

This is confusing<br> (2x+y)^2−(x−2y)^2

Iteru [2.4K]

Answer:

${(2x + y)}^{2} - {(x - 2y)}^{2}$

$< {(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} >$

$< {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} >$

${(2x)}^{2} + 2(2x)(y) + {(y)}^{2} - {(x)}^{2} - 2(x)(2y) + {(2y)}^{2}$

${4x}^{2} + 4xy + {y}^{2} - {x}^{2} - 4xy + {4y}^{2}$

${4x}^{2} - {x}^{2} + {4y}^{2} + {y}^{2}$

$= {3x}^{2} + {5y}^{2}$

5 0

2 years ago

Read 2 more answers