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irina [24]
3 years ago
6

Help!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
kozerog [31]3 years ago
3 0
She did not multiply both sides of the equation by 2.

   2x-6y =-2
<u>+ 2x+6y=3
</u><u />   4x      =1
 
x=1/4
y=5/12

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a

Step-by-step explanation:

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lyudmila [28]

Answer:

Step-by-step explanation:

You are given values for x. Plug them in to the given equations. Graph the two lines. Find the intersection. You can tell from the chart when you get the same y value for both equations

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3 years ago
hree vertices of a triangle are located at A (4, 3), B (2, 1), and C (3, 4). Which shows the correct graph of the vertices? A. A
bagirrra123 [75]

Answer: Choice A

Point A is plotted 4 units to the right and 3 units above the origin. Point B is plotted 2 units to the right of and 1 unit above the origin. Point C is plotted 3 units to the right and 4 units above the origin

====================================================

Explanation:

The point A(4,3) means we start at the origin and move 4 units to the right and 3 units up. The x and y axis are separate number lines to mark a location

B(2,1) means we move 2 units to the right and 1 unit up

C(3,4) means we move 3 units to the right and 4 units up

Each time we plot a new point, we always start at the origin.

3 0
2 years ago
The students can make 6 tickets from each sheet of paper. How many sheets of paper. How many sheets of paper are needed for 125
pantera1 [17]

Answer:

21 sheets of paper

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Which of the following equations represents a line that passes through the points
Nonamiya [84]

Answer:

Option A is correct

A. Neither

Step-by-step explanation:

Given:

Two points are given (2, 15) and (0, 5)

Let (x_{1}, y_{1})=(2,15) and (x_{2}, y_{2})=(0,5)

The slope of the line m=\frac{y_{2}- y_{1}}{x_{2}- x_{1}}

Put all known value in above equation.

m=\frac{5- 15}{0- 2}

m=\frac{-10}{-2}

m=5

So the slope of the line m=5.

The equation of the is

y=mx+b -------------------(1)

Where m is the slope of the line and b is y-intercept of the line.

Take point (0, 5) to compute the value of b.

Put x=0,y=5\ and\ m=5 in equation 1.

y=mx+b

5=5(0)+b

5=0+b

b=5

Take point (2, 15) to compute the value of b.

Put x=2,y=15\ and\ m=5 in equation 1.

y=mx+b

15=5(2)+b

15=10+b

15-10=b

b=5

So the equation of the line is.

y=mx+b

Put m and b value in above equation.

y=5x+5------------(2)

5x-y=-5

add 10 both side in equation 2.

y+10=5x+5+10

y+10=5x+15

y+10=5(x+3)

So the equation of line that passes through the point (2,15) and (0,5) is.

y=5x+5 or 5x-y=-5 or y+10=5(x+3)

Therefore, Neither the following equations represents a line that passes through the points  (2,15) and (0,5).

3 0
3 years ago
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