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Free_Kalibri [48]
3 years ago
10

I NEED HELP WITH BOTH THESE QUESTIONS ASAP

Mathematics
1 answer:
GenaCL600 [577]3 years ago
3 0
None of the above:

Mean
10+29+15+29+35+2 = 120
120/6 = 20 is the mean

120+27 = 147
147/7 = 21 is the new mean

So mean increases by 1

Median
2 10 15 29 29 35
Write the numbers in order and find the middle number, there is no middle number

2 10 15 27 29 29 35
27 is the middle number



Mode
2 10 15 29 29 35
The repeated numbers are 29

2 10 15 27 29 29 35
The repeated number, your mode is 29



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Two different radioactive isotopes decay to 10% of their respective original amounts. Isotope A does this in 33 days, while isot
Andrews [41]

Answer:

The approximate difference in the half-lives of the isotopes is 66 days.

Step-by-step explanation:

The decay of an isotope is represented by the following differential equation:

\frac{dm}{dt} = -\frac{t}{\tau}

Where:

m - Current mass of the isotope, measured in kilograms.

t - Time, measured in days.

\tau - Time constant, measured in days.

The solution of the differential equation is:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }

Where m_{o} is the initial mass of the isotope, measure in kilograms.

Now, the time constant is cleared:

\ln \frac{m(t)}{m_{o}} = -\frac{t}{\tau}

\tau = -\frac{t}{\ln \frac{m(t)}{m_{o}} }

The half-life of a isotope (t_{1/2}) as a function of time constant is:

t_{1/2} = \tau \cdot \ln2

t_{1/2} = -\left(\frac{t}{\ln\frac{m(t)}{m_{o}} }\right) \cdot \ln 2

The half-life difference between isotope B and isotope A is:

\Delta t_{1/2} = \left| -\left(\frac{t_{A}}{\ln \frac{m_{A}(t)}{m_{o,A}} } \right)\cdot \ln 2+\left(\frac{t_{B}}{\ln \frac{m_{B}(t)}{m_{o,B}} } \right)\cdot \ln 2\right|

If \frac{m_{A}(t)}{m_{o,A}} = \frac{m_{B}(t)}{m_{o,B}} = 0.9, t_{A} = 33\,days and t_{B} = 43\,days, the difference in the half-lives of the isotopes is:

\Delta t_{1/2} = \left|-\left(\frac{33\,days}{\ln 0.90} \right)\cdot \ln 2 + \left(\frac{43\,days}{\ln 0.90} \right)\cdot \ln 2\right|

\Delta t_{1/2} \approx 65.788\,days

The approximate difference in the half-lives of the isotopes is 66 days.

4 0
3 years ago
Read 2 more answers
For the following exercises, determine whether each of the following relations is a function.
irina1246 [14]

Answer:

The relation y=2x+8 is a function because the two different output values of the function have the one unique input value.

Step-by-step explanation:

The given relation is y=2x+8.

It is required to determine the relation is a function.

This solution can be obtained by using the concept of function. First write the given relation y=2x+8 and determine whether the given relation is a function.

Step 1 of 1

The given relation is y=2x+8.

This relation shows that the two different output values of the function have one unique input value and this relation is a linear function.

Hence, the relation is a function.

3 0
2 years ago
Matt has 20 marbles in a bag. 15 are red, 2 are blue, and 3 are green. What is the probability that Matt will pick a red marble
aliina [53]

Answer:

75%

Step-by-step explanation:

there is a 75% chance of getting a red marble as there is 15/20 marbles that are red

3 0
3 years ago
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S+q+5, when s = 3 and q = 3 <br> help me
Alona [7]

Answer:

11

Step-by-step explanation:

3+3+5

3+3

=6

6+5

=11

hope this was helpful! <3

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3 years ago
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A toy car has a momentum of 3 kilogram meters per second south. The car has a 1-kilogram mass. Which is the velocity of the car?
Oliga [24]
Number 4 i think..

^Tyrone
8 0
3 years ago
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