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3 years ago

5

About 11/12 of a golf course is in the fairways, 1/11 in the greens, and the rest in the trees. What part of the golf course is

in the trees?

1 answer:

Sladkaya [172]3 years ago

5 0

I believe that your question is wrong because 11/12+1/11>1

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0.1% of what number is 4?

nikklg [1K]

Let the number be x

Explanation:

0.1 % of x = 4
0.1 /100 × x = 4
1 /1000 × x =4
x = 4 ÷ 1 /1000
x = 4 × 1000
x = 4000

3 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=x%20%2B%205%20%20%5Cgeqslant%2012%20%5C%5C%20" id="TexFormula1" title="x + 5 \geqslant 12 \\

N76 [4]

Hello from MrBillDoesMath!

Answer:

x >= 7

Discussion:

x + 5 >= 12 => add -5 to both sides

x + 5 -5 >= 12 - 5 => as 5-5 = 0 and 12 =5 = 7

x >= 7

Thank you,

MrB

6 0

3 years ago

P^7n^3/p^4n^2 simplified <br> a.p^3n <br> b.p^11n^5 <br> c.(1/p^3n) <br> d.(1/p^11n^5)

Fynjy0 [20]

I think the answer is A. Cause your supposed to subtract so 7n-4n=3n, and 3-2=1 :) I hope this helps

5 0

3 years ago

A business shipped 106 packages one day. Customers are charged 4.50 for each standard delivery and 7.50 for each express deliver

zhuklara [117]

The question is incomplete:

A business shipped 106 packages one day. Customers are charged 4.50 for each standard delivery and 7.50 for each express delivery. Total shipping charges for the day were $600.00. How many of each kind of package were shipped?

Answer:

The business shipped 65 standard delivery packages and 41 express delivery packages.

Step-by-step explanation:

Since the business shipped 106 packages one day you can say that:

x+y=106, where:

x is the number of standard delivery packages

y is the number of express delivery packages

Also, you can say that the result of multiplying the price per each type of package for its amount and adding those would be equal to the total shipping charges for the day, which is:

4.50x+7.50y=600

So, you have the following equations:

x+y=106 (1)

4.50x+7.50y=600 (2)

Now, you can solve for x in (1):

x=106-y (3)

Then, you can replace (3) in (2) and solve for y:

4.50(106-y)+7.50y=600

477-4.50y+7.50y=600

3y=600-477

3y=123

y=123/3

y=41

Finally, you can replace the value of y in (3) to be able to find the value of x:

x=106-41

x=65

According to this, the answer is that the business shipped 65 standard delivery packages and 41 express delivery packages.

3 0

3 years ago

A jar contains two blue and five green marbles. A marble is drawn at random and then replaced. A second marble drawn at random.

DerKrebs [107]

corrected question:A jar contains two blue and five green marbles. A marble is drawn at random and then replaced. A second marble drawn at random. For each of the following, find the probability that: a) both marbles are blue b) both marbles are the same color c)the marbles are different in color

Answer:

Step-by-step explanation:

<u><em>The probability was done with replacement.</em></u>

Probaility of an event happening $=\frac{number of required outcomes}{number of possible outcomes}$

number of blue marbles= 2

number of green marbles=5

total number of marbles=7

(a) probability that both marbles are blue = pr(first is blue)*pr(second is blue)

$=\frac{2}{7}*\frac{2}{7}$

$=\frac{4}{49}$

(b)probability that both marbles are the same color =pr(first is blue)*pr(second is blue) + Pr(first is green)*Pr(second is green)

$=\frac{4}{49} + \frac{5}{7}*\frac{5}{7}$

$=\frac{4}{49} + \frac{25}{49}$

$=\frac{29}{49}$

(c)Probability that the marbles are different in colors=pr(first is blue)*pr(second is green) + Pr(first is green)*Pr(second is blue)

$=\frac{2}{7}*\frac{5}{7}+ \frac{5}{7}*\frac{2}{7}$

$=\frac{10}{49}+\frac{10}{49}$

$=\frac{20}{49}$

6 0

3 years ago