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Ede4ka [16]
3 years ago
6

What is the answer 8x-22=-60

Mathematics
1 answer:
solmaris [256]3 years ago
7 0

8x-22=-60\qquad|\text{add 22 to both sides}\\\\8x-22+22=-60+22\\\\8x=-38\qquad|\text{divide both sides by 8}\\\\\dfrac{8x}{8}=\dfrac{-38}{8}\\\\x=-4.75

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One stack has 6 cups, and its height is 15 cm. The other one has 12 cups, and its height is 23 cm. How many cups are needed for
Ronch [10]

Answer:

Given

Number of stacks = 2

Stack 1 = 6 cups; h1 = 15cm

Stack 2 = 12 cups; h2 = 23cm

Let's first find the average:

With an average of 4/3, to obtain the number of cups needed to obtain a height of 50m, we have:

50 / (4/3)

= 50 * 3/4

= 150/4

= 37.5

From the answer, we can see that the number of cups is not really proportional to the height of the stack, because the average of stack one and stack 2 are different.

Step-by-step explanation:

7 0
3 years ago
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Mkey [24]

The distance between two real numbers x,y is the absolute value of their difference, |x-y|. So the statement "all x that are 1/4 away from -6" is captured in the equation

|x-(-6)|=\dfrac14

or

|x+6|=\dfrac14

To solve, you can use the definition of absolute value: if x is not negative, then |x|=x; otherwise, |x|=-x.

So there are two cases to consider:

1. Suppose x+6\ge0. Then |x+6|=x+6, and the equation reduces to

x+6=\dfrac14\implies x=-\dfrac{23}4

2. Suppose x+6. Then |x+6|=-(x+6)=-x-6 and

-x-6=\dfrac14\implies x=-\dfrac{25}4

-6=-\dfrac{24}4, so the two solutions we found are correct because both -\dfrac{23}4 and -\dfrac{25}4 are indeed 1/4 away from -6.

- - -

For the question regarding inequality, you know that the absolute value must return a non-negative number. In other words, there is no x such that |x|.

6 0
3 years ago
87,521 rounded to the nearest hundred
givi [52]

Answer:

87,500

Step-by-step explanation:

Since the last 2 digits arent 5 or greater than 5 it can not be rounded to the next hundred.

3 0
3 years ago
Read 2 more answers
What is the square root of 3567
Lunna [17]

Answer:

59.72

Step-by-step explanation:

3 0
4 years ago
Which reason justifies the last step in a proof that ∆EDG ≅ ∆ADC?
Flauer [41]
Test of congruency could be the reason.
4 0
3 years ago
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