Answer:
$3.51
Step-by-step explanation:
1 pound is $2.39 so divide by 2 and round up to the nearest whole number which is $1.12. Add $1.12(The cost of 0.5 pounds) to $2.39(The cost of 1 pound) to get $3.51 as your total.
Try this option:
1. the sides of the biggest triangle are 16; x and √(16²-x²); the sides of the smallest triange are x;5 and y. The smallest triangle ~ the biggest triangle. Using the property of the similar triangles:
![\frac{x}{5} = \frac{16}{x}, \ then \ x= \sqrt{80}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7B5%7D%20%3D%20%5Cfrac%7B16%7D%7Bx%7D%2C%20%5C%20then%20%5C%20x%3D%20%5Csqrt%7B80%7D%20)
2. according to the Pyphagorean theorem (in the smallest triangle):
![y= \sqrt{ \sqrt{80^2} -5^2} = \sqrt{55}](https://tex.z-dn.net/?f=y%3D%20%5Csqrt%7B%20%5Csqrt%7B80%5E2%7D%20-5%5E2%7D%20%3D%20%5Csqrt%7B55%7D)
answer: y=√55.
Answer:
<h2>S = 9/20</h2><h2>J = 113/50</h2>
Step-by-step explanation:
![5J +2S =12.20 ........(1)\\5J+10S=15.80......(2)\\Multiply \:equation \:(1)\:by\:the\:coefficient\:of\:x\:in equation\:(2)\\\\Multiply\:equation(2)\: by\: the\: coefficient\:of \:x\: in \:equation (1)\\\\5J +2S =12.20 ........(1) \times 5\\5J+10S=15.80......(2)\times 5\\\\25J+10S=61......(3)\\25J+50S = 79......(4)\\Subtract\:equation\:(4)\:from\: equation\: (3)\\-40S =-18\\\frac{-40S}{-40}=\frac{-18}{-40}\\ S = 9/20\\](https://tex.z-dn.net/?f=5J%20%2B2S%20%3D12.20%20........%281%29%5C%5C5J%2B10S%3D15.80......%282%29%5C%5CMultiply%20%5C%3Aequation%20%5C%3A%281%29%5C%3Aby%5C%3Athe%5C%3Acoefficient%5C%3Aof%5C%3Ax%5C%3Ain%20equation%5C%3A%282%29%5C%5C%5C%5CMultiply%5C%3Aequation%282%29%5C%3A%20by%5C%3A%20the%5C%3A%20coefficient%5C%3Aof%20%5C%3Ax%5C%3A%20in%20%5C%3Aequation%20%281%29%5C%5C%5C%5C5J%20%2B2S%20%3D12.20%20........%281%29%20%5Ctimes%205%5C%5C5J%2B10S%3D15.80......%282%29%5Ctimes%205%5C%5C%5C%5C25J%2B10S%3D61......%283%29%5C%5C25J%2B50S%20%3D%2079......%284%29%5C%5CSubtract%5C%3Aequation%5C%3A%284%29%5C%3Afrom%5C%3A%20equation%5C%3A%20%283%29%5C%5C-40S%20%3D-18%5C%5C%5Cfrac%7B-40S%7D%7B-40%7D%3D%5Cfrac%7B-18%7D%7B-40%7D%5C%5C%20%20S%20%3D%209%2F20%5C%5C)
![Substitute \:9/20\:for \:x \:in\:equation\:(1)\:or \:equation\:(2)\\5J+2S = 12.20\\5J +2(9/20) =12.20\\5J +9/10=12.20\\5J=12.20-9/10\\5J=113/10\\Cross-Multiply\\50J = 113\\J = 113/50](https://tex.z-dn.net/?f=Substitute%20%5C%3A9%2F20%5C%3Afor%20%5C%3Ax%20%5C%3Ain%5C%3Aequation%5C%3A%281%29%5C%3Aor%20%5C%3Aequation%5C%3A%282%29%5C%5C5J%2B2S%20%3D%2012.20%5C%5C5J%20%2B2%289%2F20%29%20%3D12.20%5C%5C5J%20%2B9%2F10%3D12.20%5C%5C5J%3D12.20-9%2F10%5C%5C5J%3D113%2F10%5C%5CCross-Multiply%5C%5C50J%20%3D%20113%5C%5CJ%20%3D%20113%2F50)
Answer:
141,900
Step-by-step explanation:
I used the calculator :)