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pogonyaev
4 years ago
6

What is the difference between theoretical and experimental probability?

Mathematics
1 answer:
IRINA_888 [86]4 years ago
3 0
Theoretical probability is  what you would expect  the result of an experiment would be. For example if you tossed a fair coin 10 times the theoretical result would be 5 heads and 5 tails, because  probabilty of 1 toss is 1/2 for tailand 11/2 for a head.

I practice however we might get , say, 6 heads and 4 tails 
So experimental probability of e head would be 6/10 and of a tail would be 4/10.

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What is 6 x 10 x 400 + 2.5
Lorico [155]

Answer:

24,002.5

Step-by-step explanation:

6*10*400+2.5

60*400+2.5

24,000+2.5

24,002.5

Order of operations :)

3 0
3 years ago
Write two number that multiply to the value on top and add to the value on bottom
spin [16.1K]

Answer:

-10 and 5

Step-by-step explanation:

because -10 x 5 = -50 and -10 + 5 = -5!

6 0
3 years ago
if a runner finishes the 26.2. mille race in 4 hours and 37 mins and Wilson kipping finish in 4 minutes and 43 seconds per mile
Neporo4naja [7]

Answer

a) Wilson Kipsang is 7.046 miles per hour faster than the average runner.

Solution is presented below under Explanation.

b) Wilson Kipsang is 2.24 times faster than the average runner.

c) When the average runner is at mile 6, Kipsang will be at mile 13.45.

d) Kipsang's record time = 2 hours, 3 minutes, 34.6 seconds

Explanation

To solve this, we will calculate the speed of the average runner and then the speed of Wilson Kipsang

Speed = (Distance/Time)

For the average runner

Distance = 26.2 miles

Time = 4 hours 37 mins = 4 hours + (37/60) = 4.617 hours

Speed = (Distance/Time)

Speed = (26.2/4.617)

Speed = 5.675 miles per hour

For Wilson Kipsang

Distance = 1 mile

Time = 4 minutes 43 seconds = (4/60) + (43/3600) = 0.0667 + 0.01194 = 0.0786 hour

Speed = (Distance/Time)

Speed = (1/0.0786) = 12.721 miles per hour

So, now, we are asked to find how much faster than the average runner is Wilson Kipsang

Wilson Kipsang's speed = 12.721 miles per hour

Average runner's speed = 5.675 miles per hour

Wilson Kipsang is faster than the average runner by

(12.721 - 5.676) = 7.046 miles per hour

b) We are asked to find how many times faster than the average runner Wilson Kipsang is.

Let the number of times he is faster than the average runner be x

Wilson Kipsang's speed = 12.721 miles per hour

Average runner's speed = 5.675 miles per hour

(5.675) (x) = (12.721)

Divide both sides by 5.675

x = (12.721/5.675)

x = 2.24 times

c) If the average runner is at mile 6, where would Kipsang be?

To do this, we will find the time it takes the average runner to be at mile 6, then use that time to find where Kipsang would be.

Speed = (Distance/Time)

By cross multiplying, we see that

Time = (Distance/Speed)

For the average runner

Distance = 6 miles

Speed = 5.675 miles per hour

Time = (Distance/Speed)

Time = (6/5.675) = 1.057 hours

For Wilson Kipsang,

Speed = (Distance/Time)

By cross multiplying

Distance = (Speed) (Time)

Speed = 12.721 miles per hour

Time = 1.057 hours

Distance = (Speed) (Time)

Distance = (12.721) (1.057)

Distance = 13.45 miles

d) We were told that for Kipsang

1 mile = 4 minutes 43 seconds

26.2 miles = 26.2 (4 minutes 43 seconds)

26.2 miles = 26.2 (283 seconds) = 7414.6 seconds

We can then convert this further

7414.6 seconds = 2 hours, 3 minutes, 34.6 seconds

Hope this Helps!!!

4 0
1 year ago
X + 4 = 3x + 2.<br> Help with answer
Len [333]

Answer:

x=1

Step-by-step explanation:

1+4=5

3x1+2=5

8 0
3 years ago
Read 2 more answers
A caterer is making cookie trays for upcoming holiday parties. This morning she mad a 4 small trays and 4 large trays, which con
Levart [38]

Your question is not complete however, I will input what is likely to complete it.

Question:

A caterer is making cookie trays for upcoming holiday parties. This morning she mad a 4 small trays and 4 large trays, which contain a total of 288 cookies. In the evening, she made 1 small tray and 3 large trays, which contain a total of 180 cookies. How many cookies do the different sized trays contain?

Answer:

Each small tray can contain 18 cookies, while each large tray can contain 54 cookies

Step-by-step explanation:

Let assign some variables by denoting S = small trays and L = large trays

In the morning; 4S +4L = 288 --eqn 1

In the evening; 1S + 3L = 180 --eqn 2

From eqn 2, S = 180 - 3L ---eqn 3

Substitute eqn 3 into eqn 1

4(180 - 3L) + 4L = 288

720 - 12L + 4L = 288

8L = 432

L = 432/8 = 54

L = 54

Substitute L = 54 into eqn 3

S = 180 - 3L

S = 180 - 3(54)

S = 180 - 162

S = 18

Therefore, each small tray can contain 18 cookies, while each large tray can contain 54 cookies.

Note:

Use this second part of this question (my framed part of the question) to complete yours. You should get your answer adequately.

4 0
3 years ago
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