Subtract -5x2 + 10x – 1 from 6x2 X + 3.
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Answer:
The probability that the cost for someone's dog is higher than for the cat is 33.2%.
Step-by-step explanation:
With the data given, we know that the difference in cost of medical care of dogs and cats have a normal distribution with μ=-20 and σ=46.
To know the probability of the cost for the dog is higher than the cat, we have to calculate the probability of P(d>0).
Then we have to calculate z, and look up in a standarized normal distribution table.
Calculate z:
The probability of the difference being higher than 0, we have:
We can say that the probability that the cost for someone's dog is higher than for the cat is 33.2%.