If line AD is a tangent to circle B at point C, and m∠ABC = 40º, what is the measure of ∠BAC? 90º 180º 50º 40º

Mathematics

2 answers:

sveticcg [70]2 years ago

5 0

Answer:

Step-by-step explanation:

zhenek [66]2 years ago

4 0

We have a line tangent to the circle with center B at point C. We know that the angle formed between the tangent line at the point of intersection to the line extended from that point to the center of the circle is equal to 90°. In the problem, the 90° is for ∠BCA. We also know that the summation of all angles in a triangle is 180°. We have the solution below for the ∠BAC
180°=∠BAC + ∠BCA + ∠ABC
180°=∠BAC + 90° + 40°
∠BAC =50°
The answer is 50°.

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Can someone help me please

jenyasd209 [6]

Answer:

Multiply $\frac { 3 } { 4 }$ by 8.

Step-by-step explanation:

We are given the following expression and we are to find its quotient:

$\frac { 3 } { 4 }$ ÷ $\frac { 1 } { 8 }$

This can also be written as:

$\frac{\frac{3}{4}}{\frac{1}{8} }$

Since the two fractions are being divided so to change this division sign into a multiplication sign, we will take the reciprocal of the fraction in the denominator and multiply 3/4 by 8.

$\frac{3}{4} \times 8$ = 6