If line AD is a tangent to circle B at point C, and m∠ABC = 40º, what is the measure of ∠BAC? 90º 180º 50º 40º

Mathematics

2 answers:

sveticcg [70]3 years ago

5 0

Answer:

Step-by-step explanation:

zhenek [66]3 years ago

4 0

We have a line tangent to the circle with center B at point C. We know that the angle formed between the tangent line at the point of intersection to the line extended from that point to the center of the circle is equal to 90°. In the problem, the 90° is for ∠BCA. We also know that the summation of all angles in a triangle is 180°. We have the solution below for the ∠BAC
180°=∠BAC + ∠BCA + ∠ABC
180°=∠BAC + 90° + 40°
∠BAC =50°
The answer is 50°.

You might be interested in

Aaron says that all

Softa [21]

Answer:

Step-by-step explanation:

Look at the figure attached below, we know that the area of the cone is the sum of area of circle part and cone part of the figure.

to find the surface area of the cone, first measure the radius of the base and find the area of the circle part by formula $\pi r^2$ . Then measure the side (slant height) length of the cone part and find the area of the cone part by the formula $\pi rl$ .

Now the surface area of the cone is circumference of the circle plus area of the cone part.

i.e. $surface\ Area\ of\ the\ cone=\pi r^{2}+\pi rl$

From the above discussion we concluded that surface area of the cone does not depend only on the circumference of the base but also we need side length of the cone part as well thus all cones with a base circumference of 8 inches will not have the same surface area.