We have a line tangent to the circle with center B at point C. We know that the angle formed between the tangent line at the point of intersection to the line extended from that point to the center of the circle is equal to 90°. In the problem, the 90° is for ∠BCA. We also know that the summation of all angles in a triangle is 180°. We have the solution below for the ∠BAC 180°=∠BAC + ∠BCA + ∠ABC 180°=∠BAC + 90° + 40° ∠BAC =50° The answer is 50°.
