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NikAS [45]
3 years ago
5

Determine whether the number is divisible by 3.give a reason based on the tests for divisibility 72

Mathematics
1 answer:
snow_lady [41]3 years ago
5 0

72 is dividable by 3. It is divisible by 3 because when you add 7 and 2, you get 9. According to the tests for divisibility, if the sum of the digits is divisible by 3, then the whole number is. 9 is divisible by 3, therefore 72 is as well.

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Use the Perfect Square Trinomial and provide the first step to calculating 382 without a calculator.
dusya [7]

Answer:

(40-2)^2

Step-by-step explanation:

Given: (38)^2

To find: the correct option

Solution:

A binomial polynomial is a polynomial consisting of two terms.

A trinomial polynomial is a polynomial consisting of three terms.

On multiplying a binomial (x-y) to itself, a perfect square trinomial (x-y)^2 is obtained.

Here, 38=40-2

So, (38)^2=(38)(38)=(40-2)(40-2)=(40-2)^2

Here, (40-2) is a binomial and it is multiplied to (40-2) to get a perfect square trinomial (40-2)^2

7 0
4 years ago
a scientist has two solutions which she has labeled solutions A and solution B each contains salt. she knows that solution A is
loris [4]

Answer

Let x = the number of ounces of Solution A

Let y = the number of ounces of Solution B

x + y = 180        y = 180 - x

.60x + .85y = .75(180)

.60x + .85y = 135      Multiply both sides of the equation by 100 to remove the decimal points.

60x + 85y = 13500

60x + 85(180 - x) = 13500

60x + 15300 - 85x = 13500

-25x = -1800

x = 72ounces

y = 180 - 72

y = 108 ounces          

6 0
3 years ago
What is 9 - 2c + c = -13
Len [333]
9 - 2c + c = -13
9 - 3c = -13
-3c = -22
c = 7 1/3
6 0
4 years ago
Describe two different cross section shapes that can be formed by slicing a cylinder. For each shape describe how the cross sect
artcher [175]

either a rectangle or circle will be made. If you cut it horizontially you will get a circle. Vertically and you will have a rectangle

5 0
3 years ago
Write the equation of the quadratic given the following information:
xenn [34]
<span>y=a((x-h)^2)+k
Vertex=(h,k)
1. Vertex (5,-1) Point (2,4)
y=a((x-5)^2)+(-1)
f(2)=4
4=a((2-5)^2)+(-1)
4=a(-3)^2-1
4=a*9-1
5=a*9
5/9=a
y=(5/9)((x-5)^2)-1
2. Vertex (-2,0) Point (-1,-7)
y=a((x+2)^2)+0
y=a((x+2)^2)
f(-1)=-7
-7=a(-1+2)^2
-7=a(1)^2
a=-7
y=-7(x+2)
(x-h)^2=4(d)(y-k)
3. Vertex (0,0) Focus (0,2)
d=f-v
d=2
(x^2)=4(2)(y)
(x^2)=8y
f(0)=0
4. Focus (-3,4) Directrix y= -2
(x-h)^2=4(d)(y-k)
d=(4-(-2))/2=6/2=3
(x-h)^2=4(3)(y-k)
h=-3
k=(-2+4)/2=(2)/2=1
(x+3)^2=4(3)(y-1)
(x+3)^2=12(y-1)</span>
6 0
3 years ago
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