Solve the quadratic equation 3x² + 2x-4=0
Give your answers to 2 decimal places.
2 answers:
3x² + 2x - 4 = 0
Δ = b² - 4.a.c
Δ = 2² - 4 . 3 . -4
Δ = 4 - 4. 3 . -4
Δ = 52
x = (-b +- √Δ)/2a
x' = (-2 + √52)/2.3
x'' = (-2 - √52)/2.3
x' = 0,8685170918213297
x'' = -1,5351837584879966
2 Decimal places
x' = 0,87
x'' = -1,54
Answer: .8685
Step-by-step explanation:
You might be interested in
Answer:
a) 7z³+2z²-2z+1
b)2x²+3x-8
Step-by-step explanation:
a) (7z³+4z-1)+(2z²-6z+2)
7z³+2z²-2z+1
b) (5x²-2x-1)-(3x²-5x+7)
5x²-2x-1-3x²+5x-7
2x²+3x-8
The graph moves down 4 units.
Answer:
Last option
Step-by-step explanation:
X=9 this is the answer for question 19
you can use 3 quarters and 2 pennies
