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Nikitich [7]
3 years ago
7

Solve the quadratic equation 3x² + 2x-4=0 Give your answers to 2 decimal places.

Mathematics
2 answers:
GalinKa [24]3 years ago
6 0

3x² + 2x - 4 = 0

Δ = b² - 4.a.c

Δ = 2² - 4 . 3 . -4

Δ = 4 - 4. 3 . -4

Δ = 52

x = (-b +- √Δ)/2a

 

x' = (-2 + √52)/2.3    

x'' = (-2 - √52)/2.3

x' = 0,8685170918213297    

x'' = -1,5351837584879966

2 Decimal places

x' = 0,87

x'' = -1,54

Kobotan [32]3 years ago
6 0

Answer: .8685

Step-by-step explanation:

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6 0
2 years ago
Find the equation of line b described below, in slope-intercept form
Serjik [45]

Given:

Line a is perpendicular to line b .

Line a passes through the points (1,-8) and (9,-12) .

Line b passes through the point (-8, -16).

To find:

The equation of b.

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m=\dfrac{y_2-y_1}{x_2-x_1}

m_a=\dfrac{-12-(-8)}{9-1}

m_a=\dfrac{-12+8}{8}

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Product of slopes of two perpendicular lines is -1.

m_a\times a_b=-1

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Slope of line b is 2.

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y-y_1=m(x-x_1)

Line b passing through (-8,-16) with slope 2. So, equation of line b is

y-(-16)=2(x-(-8))

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7 0
3 years ago
Y = 7x - 15<br> y = 4x - 12
elena-14-01-66 [18.8K]

Answer:

Step-by-step explanation:

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(1, -8)

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