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guapka [62]
3 years ago
9

Morgan is walking her dog on an 8-meter-long leash. She is currently 500 meters from her house, so the maximum and minimum dista

nces that the dog may be from the house can be found using the equation |x – 500| = 8. What are the minimum and maximum distances that Morgan’s dog may be from the house?
Mathematics
1 answer:
Gnom [1K]3 years ago
7 0
Given:
Morgan = 500 meters from her house
Length of leash = 8 meters

minimum distance of the dog from the house 500 - 8 = 492 meters.
maximum distance of the dog from the house 500 + 8 = 508 meters.
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We know, opposite sides are parallelogram is parallel, therefore slopes are equal.

Slope of line one :

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y-5 = -0.5( x-(-4))

y-5 = -0.5x - 2

y  + 1/2x = 3

2y + x = 6

Therefore, equation of line containing the (-4, 5) is 2y + x = 6.

Hence, this is the required solution.

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3 years ago
There were 27,000 people at a ball game in Los Angeles. The day's receipts were $204,000. How many people paid $13 for reserved
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21000 people paid for general admission and 6000 paid for reserved seats. This is solved by making 2 equations. Out of 27000 people who were at game, x of them paid for general admission and y for reserved seats, thus
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13y + 6x = 204000.
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3 years ago
Evaluate 80 - 5( 2 + 7 ) + 15
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Answer:

50

Step-by-step explanation:

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Answer:

The number of bacteria B after d days is given by

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Step-by-step explanation:

The number of bacteria B in the sample triples every 10 days, this means after the first 10th day, the number of bacteria is

B = B_0 *3,

where B_0 is the initial number of bacteria in the sample.

After the 2nd 10th days, the number of bacteria is

B = (B_0 *3)*3

after the 3rd day,

B =( B_0 *3*3)*3

and so on.

Thus, the formula we get for the number of bacteria after the <em>n</em>th 10-days is

B = B_0 (3)^n

where n is is the <em>n</em>th 10-days.

Since, n is 10 days, we have

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8 0
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Solving a decimal word problem using a linear equation of the for...
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Answer:

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Therefore, Lashonda bought 5 pounds of coffee.

6 0
3 years ago
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