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Roman55 [17]
3 years ago
9

How do I plot these in order because I’ve tried it multiple times and I cannot get the right answer.

Mathematics
1 answer:
Anika [276]3 years ago
8 0

Answer:

This shape is somewhat like a square, I believe.

Step-by-step explanation:

1st Point: Inside the I quadrant (the top right), by moving 1 1/2 units to the right on the x-axis, and 4 units up.

2nd Point: Inside the IV quadrant (bottom right), by moving 1 1/2 units to the right on the x-axis, and 8 units down.

3rd Point: Inside the IV quadrant (bottom right), by moving 5 units to the right on the x-axis, and 8 units down.

4th Point: Inside the I quadrant, by moving 5 units to the right on the x-axis, and 4 units up.

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Find the pressure exerted by a force of 240 N on an area of 30 cm2. Find the answer in SI unit​
NeTakaya

Answer:

<u>Pressure</u><u> </u><u>is</u><u> </u><u>8</u><u>0</u><u>,</u><u>0</u><u>0</u><u>0</u><u> </u><u>pascals</u><u>.</u>

Step-by-step explanation:

Area:

= { \bf{ 30 \times  {10}^{ - 4}   \:  {m}^{2} }}

Pressure:

{ \bf{pressure =  \frac{force}{area} }} \\  \\  { \tt{ =  \frac{240}{30 \times  {10}^{ - 4} } }} \\  = { \tt{80000 \: pascals}}

4 0
3 years ago
Ted knows the actual distance between two cities is 150 miles. His map shows a distance of 2 inches between these cities. What i
Serjik [45]

Answer:

The scale used on his map is <u>150 miles : 2 inches</u>.

Step-by-step explanation:

Given:

Ted knows the actual distance between two cities is 150 miles. His map shows a distance of 2 inches between these cities.

Now, to find the scale Ted used on his map.

The actual distance Ted know between two cities = 150 miles.

The distance on map between these cities = 2 inches.

So, to get the scale used on his map:

\frac{The\ actual\ distance\ Ted\ know\ between\ two\ cities}{The\ distance\ on\ map\ between\ these\ cities}

=\frac{150\ miles}{2\ inches}

=150\ miles:2\ inches.

Therefore, the scale used on his map is 150 miles : 2 inches.

5 0
3 years ago
Using approciate properties find -4/7*3/5+4/7*-1/5+2/5*-4/5
slega [8]

Answer: 0.548

Step-by-step explanation:

First you need to remember the formula for PEMDAS(Parenthesis,exponents,multiplication,divison,addition,subtractio)

you can do either multiplication or divison whichever comes first, same with addition+subtraction.

the underlined means to simplify

1.<u>-0.57x3</u>/5+4/7x-1/5+2/5x-4/5

2.<u>-1.71/5</u>+4/7x-1/5+2/5x-4/5

3.-0.342+<u>4/7</u>x-1/5+2/5x-4/5

4.-0.342+0.57x<u>-1/5</u>+2/5x-4/5

5.-0.342+<u>0.57x-0.2</u>+2/5x-4/5

6.-0.342+0.114+<u>2/5</u>x-4/5

7.-0.342+0.114+<u>0.4x-4</u>/5

8.-0.342+0.114+<u>-1.6/5</u>

9.<u>-0.342+0.114</u>+-0.32

10.<u>-0.228+-0.32=-0.548</u>

<u>i did this all in one go so......</u>

8 0
3 years ago
Diana works at a clothing store. she sold 1/5 of the total number of green shirts on Monday and 3/12 of the total number of gree
Doss [256]

Answer:

Step-by-step explanation:

3/12 really is 1/4  (Divide top and bottom by 3) 3/3 = 1 and 12/3 = 4

1/5 + 1/4 = 4/20 + 5/20 = 9/20

There is something we don't know about this question. If you put a remark, I will come back and look at it.

6 0
3 years ago
True or false is a relation in which each y value has only 1 x value
boyakko [2]

Answer:

The statement is true that a function is a relation in which each y value has ONLY 1 x value.

Step-by-step explanation:

The statement is true that a function is a relation in which each y value has ONLY 1 x value.

The reason is very clear that we can not have the repeated x-values (two same x-values).

For example, given the set of the ordered pairs of a relation

{(3, a), (6, b), (6, c)}

As the same x values (x=6) has two different Y values. Hence, the stated relation is not a function.

In order to be a function, a relation must have only 1 x-value for each y-value.

Therefore, the statement is true that a function is a relation in which each y value has ONLY 1 x value.

5 0
3 years ago
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