Answer:
1: 11/4
2: 24/5
3: 2 4/5
4: 55/9
5: 8 1/5
6: 28
7: 4 1/17
8: 54
9: 39 1/2
10: 1 3/4
Step-by-step explanation:
If the condition holds true, then:
f(4) = f(5)
f(5) = f(6)
f(6) = f(7)
f(7) = f(8)
Thus,
f(4) = f(8)
f(8) = 17
Answer:
d=3d-5 or the other way around
p.s mark me as brainlist if correct
For large sample confidence intervals about the mean you have:
xBar ± z * sx / sqrt(n)
where xBar is the sample mean z is the zscore for having α% of the data in the tails, i.e., P( |Z| > z) = α sx is the sample standard deviation n is the sample size
We need only to concern ourselves with the error term of the CI, In order to find the sample size needed for a confidence interval of a given size.
z * sx / sqrt(n) = width.
so the z-score for the confidence interval of .98 is the value of z such that 0.01 is in each tail of the distribution. z = 2.326348
The equation we need to solve is:
z * sx / sqrt(n) = width
n = (z * sx / width) ^ 2.
n = ( 2.326348 * 6 / 3 ) ^ 2
n = 21.64758
Since n must be integer valued we need to take the ceiling of this solution.
n = 22
2 is in the hundred thousands place
