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alukav5142 [94]
3 years ago
7

9-2*x=35 A. -13 B. -22 C. 48

Mathematics
2 answers:
Serjik [45]3 years ago
7 0

Answer:

-13

Step-by-step explanation:

9-2/x=35

9-2/x=35

-2/x=35-9

-2/x=26

-2=26x

26x=-2

x=-1/13

irina1246 [14]3 years ago
6 0

Answer:

x= -13 (a)

Step-by-step explanation:

-2x=35-9

-2x=26

x=-13

hope this helps x.

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Is it 729 lol why would you put it as mixed number
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Suppose a particular type of cancer has a 0.9% incidence rate. Let D be the event that a person has this type of cancer, therefo
natita [175]

Answer:

There is a 12.13% probability that the person actually does have cancer.

Step-by-step explanation:

We have these following probabilities.

A 0.9% probability of a person having cancer

A 99.1% probability of a person not having cancer.

If a person has cancer, she has a 91% probability of being diagnosticated.

If a person does not have cancer, she has a 6% probability of being diagnosticated.

The question can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem we have the following question

What is the probability that the person has cancer, given that she was diagnosticated?

So

P(B) is the probability of the person having cancer, so P(B) = 0.009

P(A/B) is the probability that the person being diagnosticated, given that she has cancer. So P(A/B) = 0.91

P(A) is the probability of the person being diagnosticated. If she has cancer, there is a 91% probability that she was diagnosticard. There is also a 6% probability of a person without cancer being diagnosticated. So

P(A) = 0.009*0.91 + 0.06*0.991 = 0.06765

What is the probability that the person actually does have cancer?

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.91*0.009}{0.0675} = 0.1213

There is a 12.13% probability that the person actually does have cancer.

3 0
3 years ago
What are the dependent (y) and the independent (x) variables?
Alexandra [31]

Answer:

i donk know and i dont understand the question

Step-by-step explanation:

7 0
3 years ago
1. Quadrilateral BGTS has vertices B (-3, 4), G (-1, 3), T (-1, 1), and S (-4, 2). Graph BGTS and its image after a translation
larisa86 [58]

The image is attached with answer

<h3>What is a Quadrilateral ?</h3>

A quadrilateral is a polygon with four sides , four angles and four vertices.

It is given in the question that

Quadrilateral BGTS has vertices B (-3, 4), G (-1, 3), T (-1, 1), and S (-4, 2).

A graph has to be drawn of

its image after a translation along (5,0) and a reflection in the x-axis.​

The coordinates after translation and reflection is is B (8, -4), G (6, -3), T (6, -1), and S (7, -2).

The image is attached with the answer .

To know more about Quadrilateral

brainly.com/question/13805601

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6 0
2 years ago
Line XY bisects and is perpendicular to AB and CD. CD = 10 and XY = 24. What is the length of AP?
myrzilka [38]

Answer:

<u>AP = 13</u>

Step-by-step explanation:

See the attached figure.

CD = 10 and XY = 24

Line XY bisects and is perpendicular to AB and CD

∴ XY bisects at Y

∴ CY = 0.5 CD = 0.5 * 10 = 5

And from the geometry of the shape

P is the midpoint of XY

∴ XP = YP = 0.5 XY = 0.5 * 24 = 12

XY is perpendicular to CD

∴ ΔPYC is a right triangle at Y

∴ PC (hypotenuse) = \sqrt{PY^2+YC^2} =\sqrt{12^2+5^2}=\sqrt{144+25} =\sqrt{169} =13

From the figure AP = PC = 13

8 0
3 years ago
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