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wolverine [178]

3 years ago

9

Kyle a used 10 cups of raisins to make 5 batches of oatmeal raisin cookies. How many cups of raisins are in 1 batch of cookies?P

lease explain and show you work please.

2 answers:

zavuch27 [327]3 years ago

4 0

Because 10 cups are used to make 5 batches, you would need 2 cups to make 1 batch. To find this, I divided 10/5 to get 2. So, for 5 batches, you would do 2 x 5 to get 10 cups.

Hope this helps!

lidiya [134]3 years ago

3 0

So you have 10 total cups and 5 batches. Assuming that the raisens are evenly distributed, you get 10/5, which is 2 raisin cups per batch

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180 lb 12 oz - 79.3 kg = ___________ kg

Brrunno [24]

Answer:

$180lb\ 12 oz - 79.3kg = 2.8kg$

Step-by-step explanation:

Given

$180\ lb 12\ oz - 79.3kg$

Required

Solve

First, convert 180lb to kg

$1lb \to 0.454kg$

$180lb \to 180 *0.454kg$

$180lb \to 81.7kg$ -- to 1dp

Next, convert 12oz to kg

$1oz \to 0.03kg$

$12oz \to 12 * 0.03kg$

$12oz \to 0.4kg$ --- to 1 dp

So, the expression becomes:

$180\ lb 12\ oz - 79.3kg$

$81.7kg + 0.4kg - 79.3kg$

$= 2.8kg$

Hence:

$180lb\ 12 oz - 79.3kg = 2.8kg$

3 0

3 years ago

If BC = 5 and CD = 26, find AC.

Blababa [14]

Answer:

$AC=\sqrt{130}$

Step-by-step explanation:

AC is the geometric mean. Solve it using this proportion:

$\frac{BC}{AC}=\frac{AC}{CD}$

Now fill in the values we know:

$\frac{5}{AC}=\frac{AC}{26}$

Cross multiply to get

$(AC)^2=130$

That means that

AC = $\sqrt{130}$ , which, in decimal form is

AC = 11.40175425

3 0

3 years ago

Please someone help me‼️

Flauer [41]

Answer:

6 m

Step-by-step explanation:

The volume of a cone is found by $\frac{\pi r^2h}{3}$ , so we can plug the values in to get 6pi * r^2 / 3 = 72pi, or 6pi * r^2 = 216 pi, so r^2 = 36 and the radius is 6 m.

4 0

3 years ago

Which of the following expressions represents the distance between 3/4 and 2

Anettt [7]

Answer:

Im not sure what the following expressions are but the answer to the distance between 3/4 and 2 is 5/4 or just 1 1/4...

Not sure if this was what you were trying to ask but hope this helps

6 0

3 years ago

A bag contain 3 black balls and 2 white balls.

Troyanec [42]

Answer:

Step-by-step explanation:

Total number of balls = 3 + 2 = 5

1)

a)

$Probability \ of \ taking \ 2 \ black \ ball \ with \ replacement\\\\ = \frac{3C_1}{5C_1} \times \frac{3C_1}{5C_1} =\frac{3}{5} \times \frac{3}{5} = \frac{9}{25}\\\\$

b)

$Probability \ of \ one \ black \ and \ one\ white \ with \ replacement \\\\= \frac{3C_1}{5C_1} \times \frac{2C_1}{5C_1} = \frac{3}{5} \times \frac{2}{5} = \frac{6}{25}$

c)

Probability of at least one black( means BB or BW or WB)

$=\frac{3}{5} \times \frac{3}{5} + \frac{3}{5} \times \frac{2}{5} + \frac{2}{5} \times \frac{3}{5} \\\\= \frac{9}{25} + \frac{6}{25} + \frac{6}{25}\\\\= \frac{21}{25}$

d)

Probability of at most one black ( means WW or WB or BW)

$=\frac{2}{5} \times \frac{2}{5} + \frac{3}{5} \times \frac{2}{5} \times \frac{2}{5} + \frac{3}{5}\\\\= \frac{4}{25} + \frac{6}{25} + \frac{6}{25}\\\\=\frac{16}{25}$

2)

a) Probability both black without replacement

$=\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}$

b) Probability of one black and one white

$=\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}$

c) Probability of at least one black ( BB or BW or WB)

$=\frac{3}{5} \times \frac{2}{4} + \frac{3}{5} \times \frac{2}{4} + \frac{2}{5} \times \frac{3}{4}\\\\=\frac{6}{20} + \frac{6}{20} + \frac{6}{20} \\\\=\frac{18}{20} \\\\=\frac{9}{10}$

d) Probability of at most one black ( BW or WW or WB)

$=\frac{3}{5} \times \frac{2}{4} + \frac{2}{5} \times \frac{1}{4} + \frac{2}{5} \times \frac{3}{4}\\\\=\frac{6}{20} + \frac{2}{20} + \frac{6}{20} \\\\=\frac{14}{20}\\\\=\frac{7}{10}$

6 0

3 years ago