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3 years ago

You roll a die, winning nothing if the number of spots is odd, $1 for a 2 or a 4, and $10 for a 6.

1 answer:

4 0

Answer: The expected value is 1/6 * 1/2 * 1/3 = 1/36 the standard deviation of 1/36 = 99.7% = 1/36 * 0.997 = 0.0276944444

The mean playing twice = 1/9 =0.111111111

Step-by-step explanation:

to win $10 in one throw = 1/6 to win $1 in one throw = 2/6 and to lose is 1/2 so we have 3 probabilities and 3(3)= 9 probability combinations = 1/2 to lose 1/3 to win $2 and 1/6 to win $10 playing twice = 1/6 * 1/6 = 1/36 or 1/6* 1/2= 1/12 or 1/6 * 1/3 = 1/18 or 1/2 * 1/2 = 1/4 or 1/2 * 1/6 = 1/12 or 1/2 * 1/3 = 1/6 or 1/3 * 1/3 = 1/9 or 1/3 * 1/2 = 1/6 or 1/3 * 1/6 = 1/18 we write a list 1/36+1/12+1/18+1/4+1/12+1/6+1/9+1/6+1/18 /9 = 34/36 + 2/36 = 36/36 = 1 and 1/9 =0.111111111

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A=8, b=5, C=90 degree; Find c, A, and B<br><br> This is for the law of sine and cosine

brilliants [131]

Answer:

• c = √89 ≈ 9.434

• A = arcsin(8/√89) ≈ 57.995°

• B = arcsin(5/√89) ≈ 32.005°

Step-by-step explanation:

By the law of cosines, ...

c² = a² + b² -2ab·cos(C)

Since c=90°, cos(C) = 0 and this reduces to the Pythagorean theorem for this right triangle.

c = √(8² +5²) = √89 ≈ 9.434

Then by the law of sines (or the definition of the sine of an angle), ...

sin(A) = a/c·sin(C) = a/c = 8/√89

A = arcsin(8/√89) ≈ 57.995°

sin(B) = b/c·sin(C) = b/c = 5/√89

B = arcsin(5/√89) ≈ 32.005°

6 0

4 years ago

A hoop, a uniform solid cylinder, a spherical shell, and a uniform solid sphere are released from rest at the top of an incline.

Serjik [45]

Answer:

Step-by-step explanation:

Given

Hoop, Uniform Solid Cylinder, Spherical shell and a uniform Solid sphere released from Rest from same height

Suppose they have same mass and radius

time Period is given by

$t=\sqrt{\frac{2h}{a}}$ ,where h=height of release

a=acceleration

$a=\frac{g\sin \theta }{1+\frac{I}{mr^2}}$

Where I=moment of inertia

a for hoop

$a=\frac{g\sin \theta }{1+\frac{mr^2}{mr^2}}$

$a=\frac{g\sin \theta }{2}$

a for Uniform solid cylinder

$a=\frac{g\sin \theta }{1+\frac{mr^2}{2mr^2}}$

$a=\frac{2g\sin \theta }{3}$

a for spherical shell

$a=\frac{g\sin \theta }{1+\frac{2mr^2}{3mr^2}}$

$a=\frac{3g\sin \theta }{5}$

a for Uniform Solid

$a=\frac{g\sin \theta }{1+\frac{2mr^2}{5mr^2}}$

$a=\frac{5g\sin \theta }{7}$

time taken will be inversely proportional to the square root of acceleration

$t_1=k\sqrt{2}=1.414k$

$t_2=k\sqrt{\frac{3}{2}}=1.224k$

$t_3=k\sqrt{\frac{5}{3}}=1.2909k$

$t_4=k\sqrt{\frac{7}{5}}=1.183k$

thus first one to reach is Solid Sphere

second is Uniform solid cylinder

third is Spherical Shell

Fourth is hoop

3 0

3 years ago

Find the unknown length of the right triangle. If necessary approximate the length to the nearest thousandth

WARRIOR [948]

We are given a right triangle and we are asked to determine the hypotenuse given the measure of its sides. To do that we will use the Pythagorean theorem:

$h^2=(10km)^2+(20km)^2$

Now, we solve the square:

$h^2=100km^2+400km^2$

Now, we add the values:

$h^2=500km^2$

Now, we take the square root to both sides:

$h=\sqrt[]{500km^2}$

Solving the operations:

$h=22.361km$

Therefore, the length of the hypotenuse is 22.361 kilometers.

6 0

1 year ago

For a taxi driver, which measures must be accurate? Check all that apply.

astra-53 [7]

Answer:

Them all as he has to know how far he travels the customer rate to see is there is an increase of decrease price of gasoline to see if it's affecting g his outcome and price per miles for obvious reasons haha

3 0

3 years ago

Read 2 more answers

Is the simplified form of 2 square root of 3 + 3 square root of 3 rational?

trasher [3.6K]

$2\sqrt3+3\sqrt3=(2+3)\sqrt3=5\sqrt3-\text{It's an irrational number}$

5 0

3 years ago