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3 years ago

What is six ninths minus one third

Mathematics

2 answers:

dimaraw [331]3 years ago

7 0

Answer:

one third

Step-by-step explanation:

san4es73 [151]3 years ago

4 0

Answer: 1/3

Step-by-step explanation:

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I need help on 2,4,12 and 50 please

Tanya [424]

2. Like

4. denominators

12. 1/2

50. 25 1/10

5 0

3 years ago

Read 2 more answers

Please help with 6 and 7

Ilya [14]

Answer:

6. The number is $-5$

7. The two numbers are $10$ and $11$

Step-by-step explanation:

Question six can be re-worded to create the following expression:

$-2=\frac{4x+10}{5}$

Solve for x to find the number:

$-2=\frac{4x+10}{5}\\-10=4x+10\\-20=4x\\\frac{-20}{4} = x\\-5 = x$

Question seven can be solved by first listing the constraints (assuming x is smaller than y):

x and y are less than 20
$x + 1 = y$
$3x - 8 = 2y$

To get the numbers, we can create a system of linear equations. First, solve for $y$ in each expression:

$y = x+1$

$2y = 3x-8\\y = \frac{3}{2}x - 4$

Solve for $x$ :

$x+ 1 = \frac{3}{2}x - 4\\x + 5 = \frac{3}{2}x\\5 = \frac{3}{2}x - x\\5 = \frac{1}{2}x\\10 = x$

Solve for $y$ :

$y = x + 1\\y = 10 + 1\\y= 11$

4 0

2 years ago

Read 2 more answers

. Look at each equation and possible solution. Is the solution correct? Select Yes or No for

insens350 [35]

A. No B. No C. Yes I honestly don’t know if that’s 100% right tho

4 0

3 years ago

Write the equation of a line that is parallel to y=0.6x+3 and that passes through the point

a_sh-v [17]

A line parallel to y = 0.6x + 3 will be of the form:

$y = 0.6x + k$

where k is a constant.

It passes through (-3,-5)

Thus,

$y = 0.6x + k \\ \\ -5 = 0.6 \times (-3) + k \\ \\ -5 = -1.8 + k \\ \\k = -5 + 1.8 \\ \\ k = -3.2$

$\textbf{The equation is \: \: y = 0.6x - 3.2}$

3 0

3 years ago

Triangle P R Q is shown. Angle R P Q is 39 degrees. The length of P R is 6, the length of R Q is p, and the length of P Q is 8.

KATRIN_1 [288]

According to law of cosines the length of RQ can be written as $p^{2} =6^{2} +8^{2} -2*6*8cos(39)$ .

Given the length PR is 6 , the length of RQ is p, the length of PQ is 8 and the angle RPQ is 39 degrees.

A length of the triangle can be written as according to law of cosines if sides are given and one angle is $a^{2} =b^{2} +c^{2} -2bccos(A)$

We have to just put the values in the above equation.

as $p^{2} =6^{2} +8^{2} -2*6*8cos(39)$ .

p is the side opposite to angle given , the length of other sides are 6 and 8 and angle is 39 degrees.

Hence the side can be written as according to law of cosines if the angle is 39 degrees is as $p^{2} =6^{2} +8^{2} -2*6*8cos(39)$ .

Learn more about trigonometric functions at brainly.com/question/24349828

#SPJ10

7 0

2 years ago