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3 years ago

I NEED HELP REALLY BAD!

Mathematics

2 answers:

katen-ka-za [31]3 years ago

7 0

<h2>Answer:</h2>

<h2>Step-by-step explanation:</h2>

The area of Trapezoid is given by

A= (a+b)/2 * h

Putting the values

A = (5+23)/2 * 12

A = 168 yd²

IrinaK [193]3 years ago

7 0

Answer:

A = 168 Square Yards

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Can some one explain to me what substitution is and how to use it to solve equations?

Yakvenalex [24]

Answer:

Step-by-step explanation:

Say that your equation is 2x+4=8, x=2

you would plug in the 2 where your x is so, 2(2) +4=8

then you'd solve regularly.

Hope my answer has helped you!

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3 years ago

The question is “Mike purchased 3 DVDs and 14 video games for $203. Nick went to the same store and bought 11 DVDs and 11 video

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4 years ago

Naval intelligence reports that 99 enemy vessels in a fleet of 1818 are carrying nuclear weapons. If 99 vessels are randomly tar

oee [108]

Answer:

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

Step-by-step explanation:

The vessels are destroyed and then not replaced, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 18 means that $N = 18$

9 are carrying nuclear weapons, which means that $k = 9$

9 are destroyed, which means that $n = 9$

What is the probability that no more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X \leq 1) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,18,9,9) = \frac{C_{9,0}*C_{9,9}}{C_{18,9}} = 0.000021$

$P(X = 1) = h(1,18,9,9) = \frac{C_{9,1}*C_{9,8}}{C_{18,9}} = 0.001666$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.000021 + 0.001666 = 0.001687$

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

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3 years ago

What is 3 and 8 tenths as a decimal

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3 years ago

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Answer:

(5,15)

Step-by-step explanation:

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2 years ago

Read 2 more answers