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Lapatulllka [165]
3 years ago
7

Which does not represent the problem Shonne? Bethany has 1 3/8 yards of orange fabric. She uses 2/3 of the fabric to make a tote

bag. How many yards of fabric does Bethany use for the tote bag?
Mathematics
1 answer:
White raven [17]3 years ago
6 0

Answer:

Step-by-step explanation:

Total yard of fabric = 1 3/8 = 11/8yd

Fabric used for tote bag is 2/3 of 11/8

= 2/3 × 11/8

= 11/12 yards

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Identify each matrix A such that A^2 has identical diagonal elements?
Maksim231197 [3]

Answer:

The correct matrices are:

Matrix:

7 1 5

1 5 7

5 7 1

all diagonal elements of A^2 are: 7^2 + 1^2 + 5^2

Matrix:

9   18  27

27 -9  18

18  27 9

all diagonal elements of A^2 are: 9^2 + 27*18 + 18*27   or (-9)^2

Matrix:

8 1 6

6 8 1

1 6 8

all diagonal elements of A^2 are: 8^2 + 6*1 + 1*6

6 0
4 years ago
please help with maths work
prisoha [69]

Given:

In a right angle triangle ABC, \angle B=90^\circ,x=8.7\ m, and \theta = 45^\circ

To find:

The value of AC.

Solution:

In a right angle triangle,

\cos \theta =\dfrac{Adjacent}{Hypotenuse}

\cos \theta =\dfrac{BC}{AC}

\cos (45^\circ) =\dfrac{8.7}{AC}

\dfrac{1}{\sqrt{2}}=\dfrac{8.7}{AC}

On cross multiplication, we get

AC=8.7\times \sqrt{2}

AC=12.30365799

AC\approx 12.304

Therefore, the measure of AC is 12.304 m.

3 0
3 years ago
Can anyone do 4,5 and 6 for me plz
cricket20 [7]

For  question 4, sinA =\frac{a}{c}, cosA= \frac{b}{c}, tan B = \frac{b}{a}, sin J = \frac{j}{l}, cosK = \frac{j}{l}, tanK = \frac{k}{j}.

Question 5. Option a and question 6. Option j

Step-by-step explanation:

Step 1:

The three basic formula needed to solve these questions are:

sin\theta = \frac{oppositeside}{hypotenuse} , cos\theta = \frac{adjacentside}{hypotenuse}, tan\theta= \frac{opposite side}{adjacent side}.

Step 2:

Using the above formula, we solve the following values

sinA = \frac{oppositeside}{hypotenuse}  =\frac{a}{c}.

cosA = \frac{adjacentside}{hypotenuse} = \frac{b}{c}.

tanB= \frac{opposite side}{adjacent side}= \frac{b}{a}.

sinJ = \frac{oppositeside}{hypotenuse} = \frac{j}{l}.

cosK = \frac{adjacentside}{hypotenuse}= \frac{j}{l}.

tanK= \frac{opposite side}{adjacent side}= \frac{k}{j}.

Step 3:

For question 5, The triangle's angle = 23°, opposite side = BC inches and hypotenuse = 4 inches.

sin\theta= \frac{opposite side}{hypotenuse}. sin 23^{\circ}= \frac{BC}{4}, sin23^{\circ} = 0.3907,BC = (0.3907)(4) = 1.5628.

SO BC is 1.5628 inches, rounding this off to the nearest tenth, we get BC = 1.6 inches which is option a.

Step 4:

For question 6, The triangle's angle = 50°, opposite side = QR m the adjacent side = 8.1 m.

tan\theta= \frac{opposite side}{adjacentside}. tan 50^{\circ}=\frac{QR}{8.1}, tan50^{\circ} = 1.1917,QR = (1.1917)(8.1) = 9.65277

SO QR is 9.65277 meters, rounding this off to the nearest tenth, we get QR = 9.7 inches which is option j.

7 0
3 years ago
Determine the equation, in vertex form, of a parabola that has been:
Dennis_Churaev [7]

Answer:

a)\ y=-(x-5)^2;\\b)\ y=4x^2-5;\\c)\ (y-2)^2=4*(x+3).

Good luck!

4 0
2 years ago
Q #8 please solve my question
stealth61 [152]
The 2nd one. The one that says CD=DA, DA=ZX, AC=YZ
3 0
4 years ago
Read 2 more answers
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