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andreyandreev [35.5K]
4 years ago
15

Solving simultaneous equations with a quadratic, y=2x+5 and y=x^2-x-5

Mathematics
1 answer:
KIM [24]4 years ago
5 0
Set equal to eachother:
2x+5=x^2-x-5
0=x^2 - 3x -10
0=(x-5)(x+2)
x = -2, 5
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