I need help ! Please help me

Mathematics

2 answers:

kifflom [539]3 years ago

5 0

You can do this !

Since d=3, take your pencil and write the fraction again,
except wherever 'd' appears, write a '3' there instead.

Then you'll have a fraction with nothing but numbers in it, and
you can easily simplify and find the value of the fraction.

I did it in my head as I was looking over the picture, and
I found that the value of the fraction is between 5 and 10.
I don't want to just hand you the answer, because I know
that you can do it.

Mazyrski [523]3 years ago

4 0

4d² / (d+1) when d=3;
therefore:

4(3)² / (3+1)=4(9) / 4=9

Answer:4d² / (d+1) when d=3 is equal to 9.

You might be interested in

Help with triangles 8th grade

Vanyuwa [196]

7 is 45 degrees ndhdhdhdjdj

7 0

3 years ago

Two construction contracts are to be randomly assigned to one or more of three firms: I, II, and III. Any firm may receive both

vichka [17]

Answer:

The owner's total profit is $120,000.

Step-by-step explanation:

Assume that:

X₁ = contract is assigned to firm 1

X₂ = contract is assigned to firm 2

The sample space for assigning the two contracts is:

S = {(I, I), (I, II), (I, III), (II, I), (II, II), (II, III), (III, I), (III, II) and (III, III)}

There are total of 9 possible combinations.

So, the probability of selecting any of the combination is, 1/9.

Compute the probability distribution of X₁ and X₂ as follows:

X₁ P (X₁) X₂ P (X₂)

0 4/9 0 4/9

1 4/9 1 4/9

2 1/9 2 1/9

Compute the expected values of X₁ and X₂ as follows:

$E(X_{1})=\sum X_{1}\cdot P(X_{1})\\\\=(0\times\frac{4}{9})+(1\times\frac{4}{9})+(2\times\frac{1}{9})\\\\=\frac{6}{9}\\\\=\frac{2}{3}$ $E(X_{2})=\sum X_{2}\cdot P(X_{2})\\\\=(0\times\frac{4}{9})+(1\times\frac{4}{9})+(2\times\frac{1}{9})\\\\=\frac{6}{9}\\\\=\frac{2}{3}$