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pychu [463]
3 years ago
10

Which expression has a value of 13?

Mathematics
2 answers:
fgiga [73]3 years ago
3 0
A because all of the rest dosent equal up to 13
Norma-Jean [14]3 years ago
3 0

Step-by-step explanation

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Y = 4x + 7 at x = -2 ?
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Answer:

-1=y

Step-by-step explanation:

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HELP PLEASE IM A WEEK BEHIND!!!
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Step-by-step explanation:

Week 1 = 78

Week 2 = 100

Week 3 = 122

Week 4 = 154

Week 5 = 173

Week 6 = 194

Week 7 = 213

Week 8 = 131

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A cylinder has a radius of 5 inches and height of 20 inches.which is the surface area of the cylinder?
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1. 1187 square inches

Step-by-step explanation:

Good Job!

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2 years ago
Simplify this expression 3x+6x
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Since both 3x and 6x have the variable x in it, we can just go ahead and add 3 and 6.

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4 0
3 years ago
Read 2 more answers
Question 7: Solve this system<br><br> A.(15, 10)<br> B.(-15, 10)<br> C.(-10, 25)<br> D.(10, 15)
Alexandra [31]

Answer:

D. (10, 15)

Step-by-step explanation:

Hi there!

We are given the following system:

\frac{1}{2}x+y=20

x+4y=70

And we want to solve it (find the values of x and y).

Let's use substitution for this problem, where we will isolate one variable on one side, while the other side contains an expression with the other variable. Then, we use the expression to solve for the variable that the expression contains, then use the value of that variable to solve for the aforementioned isolated variable.

Subtract \frac{1}{2}x from both sides in the first equation

y=20-\frac{1}{2}x

Now substitute 20-\frac{1}{2}x as y in x+4y=70

x+4(20-\frac{1}{2}x)=70

Do the distributive property

x+80-2x=70

Combine like terms on the left

-x+80=70

Subtract 80 from both sides

-x=-10

Multiply both sides by -1

x=10

We found the value of x. Now let's use that value to find what y is

Since we know that y=20-\frac{1}{2}x and x=10, we can substitute 10 as the value of x to solve for y

In that case,

y=20-\frac{1}{2}(10)

Multiply

y=20-5

Subtract

y=15

The answer is x=10, y=15, or as a point, <u>(10, 15), aka D</u>

Hope this helps!

4 0
3 years ago
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