What does it mean for a product of factors to be expressed using component?

1 answer:

3 0

Mathematics. one of two or more numbers, algebraic expressions, or the like, that when multiplied together produce a given product; a divisor:
6 and 3 are factors of 18. i Guess

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Can I get help on this please

ryzh [129]

Answer:

Step-by-step explanation:

<FIL and <AIN are Vertical angles.

Vertical angles are always congruent.

Congruent means the same or equal.

8 0

3 years ago

Thomas Vega offers to pay $59 of the March cell phone bill. Each of the other 4 members of the family agrees to split the rest o

bija089 [108]

59×2=118 cost of bill.
59÷4=14.75 for the other 4 if the bill was 118 assuming Thomas pays half.

or...59 ×5=295
assuming they all pd 1/5 of the bill

6 0

3 years ago

Someone please be awesome and help me please :(

solong [7]

Answer:

$(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0$

$(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}$

$x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}$

Step-by-step explanation:

$x^2+\frac{b}{a}x+\frac{c}{a}=0$

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared. Whatever you add in, you must take out.

$x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

Now we are read to write that one part (the first three terms together) as a square:

$(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

I don't see this but what happens if we find a common denominator for those 2 terms after the square. (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

$(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0$