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RUDIKE [14]
3 years ago
9

What is the value of cos(infinity)?

Mathematics
2 answers:
Monica [59]3 years ago
3 0
The problem ask to find the value of the cos(infinity) and the best answer, base on my further calculation and formulation that came up to a solution that leads me to an answer that the cos(infinity) is undefined but it has a range of (-1,1). I hope you are satisfied with my answer and feel free to ask for more 
fomenos3 years ago
3 0

Answer:

undefined

Step-by-step explanation:

Cosine is an oscillatory function between (1,-1). te value of cosine (infinity)as no value, hence it can not be defined. In other words, it does not either tend to positive or to negative infinity, or converge on any given finite number as a limit

Cosine is the ratio of the  adjacent of a right angle triangle over its hypotenuse side.

cos∞=undefined

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olga_2 [115]

Answer:

2, 3

Step-by-step explanation:

The graph of quantities in direct proportion.

Is a straight line passing through the origin, thus

the line always crosses the y- axis at |(0, 0 )

Thus the y- intercept is 0

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3 years ago
Suppose a basketball player has made 184 out of 329 free throws. If the player make the next two free throws, I will pay you $24
Marta_Voda [28]
Given that the player made 184 out of 329 throws, the probability of making the next throw will be:
P(x)=[Number of shots made]/[Total number of throws]
=184/329
=0.559
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Ice cream vs temperature
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What is 286 over 465 in simplest form?
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\frac{286}{465
}
7 0
3 years ago
where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤
marusya05 [52]

THIS IS THE COMPLETE QUESTION BELOW

The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.

Answer

$168.27

Step by step Explanation

Given p=90000/400+3x

With the limits of 40 to 50

Then we need the integral in the form below to find the average price

1/(g-d)∫ⁿₐf(x)dx

Where n= 40 and a= 50, then if we substitute p and the limits then we integrate

1/(50-40)∫⁵⁰₄₀(90000/400+3x)

1/10∫⁵⁰₄₀(90000/400+3x)

If we perform some factorization we have

90000/(10)(3)∫3dx/(400+3x)

3000[ln400+3x]₄₀⁵⁰

Then let substitute the upper and lower limits we have

3000[ln400+3(50)]-ln[400+3(40]

30000[ln550-ln520]

3000[6.3099×6.254]

3000[0.056]

=168.27

the average price p on the interval 40 ≤ x ≤ 50 is

=$168.27

8 0
3 years ago
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