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4 years ago

M^ 1/3 ÷ m^ 1/5. Picture Below. does it equal 1/15?

Mathematics

1 answer:

jonny [76]4 years ago

4 0

$\cfrac{m^{ \frac{1}{3} }}{m^{ \frac{1}{5} }} =m^{ \frac{1}{3}- \frac{1}{5} }=m^{ \frac{5-3}{15} }=m^{ \frac{2}{15} } = \sqrt[15]{m^2}$

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A standard deck of playing cards contains 52 cards, equally divided among four suits(hearts, diamonds, clubs, and spades). Each

algol [13]

What are you asking me ? Do you have a picture I can look at ?

3 0

3 years ago

S=2(lw+lh+wh) solve for w

wolverine [178]

we have

$s=2(lw+lh+wh)$

Solve for w means that clear variable w

$s=2(lw+lh+wh)\\s=2lw+2lh+2wh$

Group terms that contain the variable w, and move the other terms to the opposite side of the equation

$(s-2lh)=(2lw+2wh)$

Factor the variable w

$(s-2lh)=w(2l+2h)$

Divide both sides by $(2l+2h)$

$(s-2lh)/(2l+2h)=w(2l+2h)/(2l+2h)$

$w=(s-2lh)/(2l+2h)$

therefore

the answer is

$w=(s-2lh)/(2l+2h)$

7 0

3 years ago

Read 2 more answers

Use the survey results to find the probability that a respondent has a pet, given that the respondent has had a pet.

Elena-2011 [213]

Answer:

Probability that the respondent has a pet given that the respondent has had a pet is $\frac{37}{81}$ or 0.46.

Step-by-step explanation:

We are given the following results below;

37% have a pet now and have had a pet.

63% do not have a pet now.

81% have had a pet.

19% do not have a pet now and have never had a pet.

Let event B = respondent has a pet now

Now, Probability that the respondent has had a pet = P(A) = 0.81

Probability that the respondent has a pet now and has had a pet = $P(A \bigcap B)$ = 0.37

So, Probability that the respondent has a pet given that the respondent has had a pet is given by = P(B/A)

This conditional probability is solved as ;

P(B/A) = $\frac{P(A \bigcap B)}{P(A)}$

= $\frac{0.37}{0.81}$ = 0.46.

3 0

4 years ago

What is the answer to this math question 2 1/12-5 5/6

AleksandrR [38]

The solution is:

$2\frac{1}{12} - 5\frac{5}{6} = \frac{-15}{4} \text{ or } -3.75$

Solution:

We have to solve the given expression

Given expression is:

$2\frac{1}{12} - 5\frac{5}{6}$

Let us first convert the mixed fraction to improper fraction

Multiply the whole number part by the fraction's denominator.

Add that to the numerator.

Then write the result on top of the denominator.

Thus we get,

$2\frac{1}{12} = \frac{2 \times 12 + 1}{12} = \frac{25}{12}$

$5\frac{5}{6} = \frac{ 5 \times 6 +5}{6} = \frac{35}{6}$

Thus the given expression becomes,

$2\frac{1}{12} - 5\frac{5}{6} = \frac{25}{12} - \frac{35}{6}$

Make the denominators same for easier calculations

$2\frac{1}{12} - 5\frac{5}{6} = \frac{25}{12} - \frac{35 \times 2}{6 \times 2}\\\\2\frac{1}{12} - 5\frac{5}{6} = \frac{25}{12} - \frac{70}{12}\\\\2\frac{1}{12} - 5\frac{5}{6} = \frac{25-70}{12}\\\\2\frac{1}{12} - 5\frac{5}{6} =\frac{-45}{12}$

Reducing to lowest terms, we get

$2\frac{1}{12} - 5\frac{5}{6} = \frac{-15}{4}$

In decimal form, we get

$\rightarrow \frac{-15}{4} = -3.75$

Thus the solution is:

$2\frac{1}{12} - 5\frac{5}{6} = \frac{-15}{4} \text{ or } -3.75$

6 0

4 years ago

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katrin [286]

A.
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3 years ago