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Artist 52 [7]
3 years ago
8

Algebra 2 help please

Mathematics
1 answer:
nikdorinn [45]3 years ago
5 0
The answer will be D
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How do I solve this problem 34=p+19
NARA [144]

Hello,

34 = p + 19

34 - 19 = p + 19 - 19

15 = p

p = 15

4 0
2 years ago
(Fog)(x) where f(x)=1/x^2+3 and g(x)= square root x-2
Sati [7]

Answer:

(fog)(x) = 1/(x-2) + 3

Step-by-step explanation:

f(x) = 1/x² +3        g(x) = √(x-2)

(fog)(x) = f(g(x)) = f( √(x-2)) = 1/(√(x-2))² +3

(fog)(x) = 1/(x-2) + 3

5 0
3 years ago
A, B, and C are points on the circumference of a circle, centre 0. AOB is a diameter of the circle. Prove that angle ACB is 90°
ki77a [65]

Answer:

Kindly refer to explanation.

Step-by-step explanation:

Given that:

A,B and C are 3 points on circumference of circle with centre O.

AOB is diameter.

Kindly refer to the attached image.

To prove:

\angle ACB = 90^\circ

Solution:

Let \angle A = x and \angle B = y.

<em>Construction</em>: Join point  A with centre O.

Considering \triangle AOC:

Side AO = OC because both are the radius.

Angles opposite to equal sides in a triangle are equal.

Therefore, \angle ACO=\angle A=x

Considering \triangle BOC:

Side BO = OC because both are the radius.

Angles opposite to equal sides in a triangle are equal.

Therefore, \angle BCO=\angle B=y

\angle ACB = \angle ACO + \angle BCO = x+y ...... (1)

Now, in \triangle ABC:

Using angle sum property of triangle:

\angle A + \angle B + \angle ACB =180^\circ\\\Rightarrow x+y+x+y=180^\circ\\\Rightarrow 2(x+y)=180^\circ\\\Rightarrow x+y=90^\circ

By equation (1):

\angle ACB = 90^\circ

Hence proved.

5 0
3 years ago
The product of two numbers is 1856. The sum is ninety. What is the difference of these two numbers?
deff fn [24]

Answer is 26:

58 x 32 is 1856

58 + 32 is 90

and 58 - 32 is 26!

hope it helped!

7 0
4 years ago
Read 2 more answers
Please help answering questions 215 and 216.
kodGreya [7K]

Problem 215

Check out the attached image. Line up the letters ABC and CDE so the first set of letters are over the second set of letters. Order is important here. Note how A corresponds to C (second C), B corresponds to D, and (the first) C corresponds to E.

We have this mapping:

A <--> C

B <--> D

C <--> E

This means...

Angle BAC corresponds to Angle DCE (red angles)

Angle ABC corresponds to Angle CDE (blue angles)

Angle BCA corresponds to Angle DEC (green angles)

It also means...

Side BC corresponds to Side DE (red sides)

Side AC corresponds to Side CE (blue sides)

Side AB corresponds to Side CD (green sides)

Check out the attached image which I hope clears up any confusion you may have. Often I think it helps to represent stuff like this in a visual way.

============================================

Problem 216

Answer: True

Since triangle ABC is congruent to triangle DEF, this means that side AB is congruent to side ED. These are corresponding sides. Since AB = 6, this means ED = 6 as well.

8 0
3 years ago
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