The tension on each segment of the clothesline is : 110 N
<u>Given data : </u>
mass of object = 100 n = 10 kg
Horizontal distance of clothesline = 4 m
middle of clothesline sag s by : 1m
<h3 /><h3>Determine the tension on each segment of clothesline</h3>
<u>First step</u> : calculate the horizontal angle made by the sagging
β = arctan ( 1 m / 2m ) ----- ( 1 )
= arctan ( 0.5 )
≈ 26.57°
Note : Tension in th y axis ( Ty ) = Tsinβ
Therefore :
Tension on each segment can be calculated using the formula below
2Tsinβ - mg = 0
solve for T
T = mg / 2sinβ
= ( 10 * 9.8 ) / 2 * sin 26.57°
= 98 / 0.89
= 110 N
Hence we can conclude that the tension on each segment of the clothesline is : 110 N
Learn more about Tension calculations : brainly.com/question/24994188
Answer: C. Establishing the Tuskegee Institute
Explanation:
Answer:
(a) In this case, small bugs are more likely to have relative fitness on the new food source.
(b) A change that will occur in bug morphology is that the female bugs will turn out to be the same size as the male bugs.
(c) In terms of behavior, the bugs will experience less competition towards reproducing early.
(d) Yes, the dispersing bug would have higher fitness as they will be able to easily get access to new resources once the previous one has run out, whereas the bugs with less developed fight muscles will not be able to do so.
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Answer:
Jupiter, Saturn, Uranus, and Neptune
Explanation:
Only gas giants have rings, so Mercury, Venus, Earth, and Mars are out of the answer choices.
According to NASA, only Jupiter, Saturn, Uranus, and Neptune (all of our gas giants), have rings.
