Financially, it probably makes more sense to:

When they think of where they live now or where they were born, most people will say "my city," or "my hometown." Generally spea

torisob [31]

I love the way of speaking with youuu about this game but eh ni hun

4 0

3 years ago

A mixture of pentadecane and heptadecane can be separated by.

Blababa [14]

Answer:

Explanation:

A mixture of pentadecane and heptadecane can be separated by amides.

7 0

2 years ago

Classify each of the following as a pure substance, homogeneous mixture, solution, or colloid.

Alexus [3.1K]

Acetic acid and ether are pure substance because they can not be further broken down.

<h3>What is a homogeneous mixture?</h3>

A homogenous mixture consists only of single phase. A solution is comprised of a solute and a solvent while a colloid is a false solution.

The following is a classification of each of the items;

1- Acetic acid - pure substance

2- Ether - pure substance

3- Vinegar - homogeneous mixture

4- Gravy - colloid

5- Beef stew - colloid

6- Seltzer water - solution

7- Salad - colloid

Learn more about homogenous mixture:brainly.com/question/24898889

#SPJ1

Mising parts;

Classify each of the following as a pure substance, homogeneous mixture, solution, or colloid.

1- Acetic acid

2- Ether

3- Vinegar

4- Gravy

5- Beef stew

6- Seltzer water

7- Salad

3 0

2 years ago

Your class has 27 students.

vivado [14]

Answer:

18

Explanation:

27 divided by 3 is 9. 9 times 2 equals 18.

3 0

3 years ago

Read 2 more answers

In a recent year, about 22% of Americans 18 years and older are single. What is the probability that in a random sample of 200 A

Pie

Using the normal approximation to the binomial, it is found that there is a 0.0107 = 1.07% probability that more than 30 are single.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The binomial distribution is the probability of x successes on n trials, with p probability of a success on each trial. It can be approximated to the normal distribution with $\mu = np, \sigma = \sqrt{np(1-p)}$ .

In this problem, the proportion and the sample size are, respectively, p = 0.22 and n = 200, hence:

$\mu = np = 200(0.22) = 44$

$\sigma = \sqrt{np(1 - p)} = \sqrt{200(0.22)(0.78)} = 5.8583$

The probability that more than 30 are single, using continuity correction, is P(X > 30.5), which is <u>1 subtracted by the p-value of Z when X = 30.5</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{30.5 - 44}{5.8583}$

Z = -2.3

Z = -2.3 has a p-value of 0.0107.

0.0107 = 1.07% probability that more than 30 are single.

More can be learned about the normal distribution at brainly.com/question/24663213

6 0

2 years ago