Answer:
185.68 cm3
Step-by-step explanation:
SA = 2 (L x W) + 2 (L x H) + 2 (W x H)
= 2 (8.2 x 3.4) + 2 (8.2 x 5.6) + 2 (3.4 x 5.6)
= 2 (27.88) + 2 (45.92) + 2 (19.04)
= 55.76 + 91.84 + 38.08
SA = 185.68 cm3
Yes, if all 8 of the students shared the cost of $100 dollars equally, that would mean each student paid $12.50.
Answer:
The value is 
Step-by-step explanation:
From the question we are told that
The weight of the bucket is 
The depth of the well is 
The weight of the water is 
The rate at which the bucket with water is pulled is 
The rate of the leak is 
Generally the workdone is mathematically represented as
]
Here G(x) is a function defining the weight of the system (water and bucket ) and it is mathematically represented as
Here I is the rate of water loss in lb/ft mathematically represented as
=> 
=> 
So
=> 
So
]
=> ![W = [47x - \frac{0.1x^2}{2} ]|\left 60} \atop {0}} \right.](https://tex.z-dn.net/?f=W%20%3D%20%20%5B47x%20-%20%5Cfrac%7B0.1x%5E2%7D%7B2%7D%20%5D%7C%5Cleft%2060%7D%20%5Catop%20%7B0%7D%7D%20%5Cright.)
=> ![W= [47(60) - 0.05(60)^2]](https://tex.z-dn.net/?f=W%3D%20%5B47%2860%29%20-%200.05%2860%29%5E2%5D)
=>
Answer:
D.
Step-by-step explanation:
I graphed it. They are both not in the same qudrant because both their x and y values are opposites. This led me to believe that they were in quadrants digaonal of each other, meaning the answer was D, because if you flipped the point across the x or y axis and then flipped it again across the other axis, it would be that point. Just in case, I graphed it. Please tell me if I'm wrong :)
Answer:
The probability that a randomly chosen person has measles antibodies in his/her blood if the new test is positive = 0.9796
Step-by-step explanation:
The event that someone tests positive = P(T)
The event that someone has antibodies = P(A)
The event that someone does not have antibodies = P(A')
The new test was positive when administered to 96% of those who have the antibodies.
This probability = P(T n A) = 0.96
The new test gave positive results in 2% of those who do not have them.
This probability = P(T n A') = 0.02
The probability that a randomly chosen person has measles antibodies in his/her blood if the new test is positive = P(A|T)
This conditional probability is given as
P(A|T) = P(T n A) ÷ P(T)
P(T) is given as
P(T) = P(T n A) + P(T n A') = 0.96 + 0.02 = 0.98
P(A|T) = P(T n A) ÷ P(T) = 0.96 ÷ 0.98 = 0.9796
Hope this Helps!!!
