Ok so student in cleveland walks 2.5 miles away from cleveland every hour from 8
so the distance, x is x=2.5t
the riding one rides 4 hours later, so t-4
11 mph
y=11(t-4)
A. x=2.5t
y=11(t-4)
when do they meet is when the distance when they are equal or when x=y
2.5t=x=y=11(t-4)
solve for t
2.5t=11(t-4)
2.5t=11t-44
-8.5t=-44
divide both sides by -8.5
t=5.17647
answer is 5.18 hours
A.
x=2.5t
y=11(t-4)
B. 5.18 hours
The answer is A. y = [x] -2
Answer:
The answer is (-4/3)
Step-by-step explanation:
3(x − 4) = 12x
Multiply (x – 4) by 3 we get,
3(x – 4) = 12x
3x – 12 = 12x
3x – 12x – 12 + 12 = 12x – 12x + 12
-9x = 12
-9x/(-9) = -12/9
x = -4/3
Thus, The value of x is -4/3
<u>-TheUnknownScientist 72</u>
Answer:
So, to 1 d.p. 7 is about 23% out of 30. (7 of 30=23%)
Step-by-step explanation:
7/30 x 100 =23.3333333333% or 70/3%.
