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3 years ago

Can anyone help me with this geometry test please like I will do anything!! I will give brainlist!!

Mathematics

2 answers:

sammy [17]3 years ago

4 0

Answer:

It c

Step-by-step explanation:

N76 [4]3 years ago

4 0

the answer is :

C. All squares are parallelogram but all parallelograms aren't squares,

since square has it's opposite sides parallel and equal and their diagonals also bisects each other, so we conclude that all squares are kind of special parallelograms, but a parallelogram can't be a square because it don't necessarily have all its sides equal and each angle measuring 90°.

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The coordinate of M is 3.5 and MN

jonny [76]

Subtract the point A x-coordinate from the midpoint x-coordinate (final-initial) to find the distance between them. This will give you 3. Multiply the by 2 because the midpoint is halfway between point A and B.

8 0

3 years ago

a plane flies 5.0km due north from a point O and then 6.0km on a bearing of 060° the pilot then changes course on a bearing of 1

Virty [35]

The plane flies a distance of approximately 10.536 kilometers in straight line and with a bearing of approximately 035°.

A plane that travels a distance $r$ , in kilometers, with a bearing of $\theta$ sexagesimal degrees can be represented in standard position by means of the following expression:

$\vec r = r\cdot (\sin\theta, \cos \theta)$ (1)

We can obtain the resulting vector ( $\vec R$ ) by the principle of superposition:

$\vec R = \Sigma_{i=1}^{n} [r_{i}\cdot (\sin \theta_{i}, \cos \theta_{i})]$ (2)

If we know that $r_{1} = 5\,km$ , $\theta_{1} = 0^{\circ}$ , $r_{2} = 6\,km$ , $\theta_{2} = 60^{\circ}$ , $r_{3} = 4\,km$ and $\theta_{3} = 120^{\circ}$ , then the resulting vector is:

$\vec R = 5\cdot (\sin 0^{\circ}, \cos 0^{\circ}) + 6\cdot (\sin 60^{\circ}, \cos 60^{\circ}) + 4\cdot (\sin 120^{\circ}, \cos 120^{\circ})$

$\vec R = (5\sqrt{3}, 6) \,[km]$

The magnitude of the resultant is found by Pythagorean theorem:

$\|\vec R\| = \sqrt{R_{x}^{2}+R_{y}^{2}}$

And the bearing is determined by the following inverse trigonometric relationship:

$\theta_{R} = \tan^{-1} \left(\frac{R_{y}}{R_{x}}\right)$ (3)

If we know that $R_{x} = 5\sqrt{3}\,km$ and $R_{y} = 6\,km$ , then the magnitude and the bearing of the resultant is:

$\|\vec R\| = \sqrt{(5\sqrt{3})^{2}+6^{2}}$

$\|\vec R\| \approx 10.536\,km$

$\theta_{R} = \tan^{-1} \left(\frac{6}{5\sqrt{3}} \right)$

$\theta_{R} \approx 34.715^{\circ}$

The plane flies a distance of approximately 10.536 kilometers in straight line and with a bearing of approximately 035°.

To learn more on vectors, we kindly invite to check this verified question: brainly.com/question/21925479

6 0

3 years ago

Anyone help with this question please..

STALIN [3.7K]

Answer:

x>3

Step-by-step explanation:

then reason is x is the black bold line and x the line is larger than 3 so the equation is x>3

pls brainliest

3 0

3 years ago

Read 2 more answers

What is the answer to 4x + 26

worty [1.4K]

Answer:

This cannot have an answer since this is a expression not a equation. If it was something like 4x+26=100, there will be a answer. but this cannot have an answer.

5 0

3 years ago

Read 2 more answers

Bill brought 8 shirts, 6 pairs of shorts and 3 pairs of shoes to camp. How many different outfits consisting of a shirt, a pair

Ilya [14]

144 outfits, I believe.

8 X 6 X 3= 144

3 0

3 years ago